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navik [9.2K]
4 years ago
9

A glass plate (n = 1.64) is covered with a thin, uniform layer of oil (n = 1.28). A light beam of variable wavelength from air i

s incident normally on the oil surface. Observation of the reflected beam shows constructive interference at 605 nm. Determine the minimum non-zero thickness of the oil film.
Physics
1 answer:
Makovka662 [10]4 years ago
8 0

Answer:

Explanation:

This is case of interference in thin films

for constructive interference in thin film the condition is

2μ t = (2n+1)λ/2    ;  μ is refractive index of oil , t is thickness of oil , λ is wave length of light .

2 x 1.28 x t = λ/2 , if n = 0

2 x 1.28 x t = 605 /2

t = 118.16 nm .

the minimum non-zero thickness of the oil film required = 118.16 nm.

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a spacecraft that seems to be motionless in deep space is given some type of quick push. which statement describes what will hap
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An applied force applied causes a body such as the spacecraft to move. The magnitude of the force determines the change in the velocity

What will happen to the spacecraft is given by option C. from among the possible question options.

C. The spacecraft will begin to move and it will continue moving until it is stopped by an equal and opposite force

Reason:

<em>The possible question options obtained from a similar question includes;</em>

<em>A. The spacecraft will move for some time then stop slowly</em>

<em>B. Air resistance will prevent the spacecraft from moving</em>

<em>C. The spacecraft will begin to move and the motion will continue until a force equal and opposite to the applied force stops it</em>

<em>D. The quick push will not cause the spacecraft to move, as a quick push works on Earth only</em>

The state of the space craft = Motionless

Location of the spacecraft = Deep space

Type of force applied = Quick push

The statement that describes what will happen = Required

Solution;

Let <em>F</em>, represent the force applied, and let Δt be the duration of the applied force, we have;

The impulse of the force, F × Δt = m·(v₂ - v₁)

Where;

m = The mass of the spacecraft

v₁ = The initial velocity of the spacecraft = 0

v₂ = Final velocity of the spacecraft

Plugging in v₁ = 0, gives;

F × Δt = m·v₂

The space craft is given a velocity, <em>v₂</em>, and according to Newton's First Law of Motion, it continues moving in a straight line until another force acts on it

Therefore, the correct option is option C. <u>The spacecraft will begin to move and the motion will continue until it is stopped by an equal and opposite force</u>

<u />

Learn more about Newton's First Law of Motion here:

brainly.com/question/20841616

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