Local currents are often formed as a result of ____

An automobile traveling along a straight road increases its speed from 30.0 m/s to 50.0 m/s in a distance of 180 m. If the accel

inessss [21]

Answer:

4.5sec

Explanation:

From the question above, the following are the parameters that are given

u= 30m/s

v= 50m/s

s= 180m

First of all we have to find the acceleration by using the third equation of motion

V^2= U^2 + 2as

50^2= 30^2 + 2(a)(180)

2500= 900 + 360a

Collect the like terms

2500-900= 360a

1600=360a

Divide both sides by the coefficient of a which is 360

1600/360=360a/360

a= 4.44m/s

The next step is to find the time. To do this we will have to use the first equation of motion

v= u + at

50= 30 + 4.44t

Collect the like terms

50-30= 4.44t

20= 4.44t

Divide both sides by the coefficient of t which is 4.44

20/4.44= 4.44t/4.44

t= 4.5sec

Hence 4.5secs elapses while the auto moves at a distance of 180m

8 0

3 years ago

Solids that have flat sides and a repeating pattern of atoms are called ______________.

DiKsa [7]

they are called crystals

7 0

4 years ago

What kinds of bonds can happen between the elements of a compound

Anit [1.1K]

What kinds of bonds can happen between the elements of a compound?

<span>Covalent and Ionic</span>

4 0

3 years ago

Mer and count Assessment items Assessment started:

RoseWind [281]

Answer:

Asteroids

Explanation:

Asteroids are the small and large block of rocks that are found to be scattering space. There are numerous asteroids present in the asteroid belt which is located between the planet of Mars and Jupiter. These range from a few meters to hundreds of kilometers. They move so rapidly, at about 80,000 km/hr and there occurs constant collision with one another. These asteroids sometimes enter into the atmosphere of earth, which can cause a great mass extinction event.

These are believed to be the remnants particles that are present in space right after the formation of the solar system.

5 0

3 years ago

I NEED PHYSICS HELP? THE QUESTION IS IN THE PIC

Marina CMI [18]

Speed of the block at the bottom of the incline: 5.42 m/s

The first part of the problem can be solved by using the law of conservation of energy. Since the ramp is frictionless, the initial gravitational potential energy of the block at the top of the ramp is converted into kinetic energy at the bottom:

$mgh = \frac{1}{2}mv^2$ (1)

where

m is the mass of the block

g = 9.8 m/s^2 is the acceleration of gravity

h is the initial height of the block

v is the speed of the block at the bottom

The initial height of the block is equal to the height of the ramp, so

$h=L sin \theta$ (2)

where

L = 3.00 m is the length of the ramp

$\theta=30^{\circ}$ is the angle of the ramp

Substituting (2) into (1) and re-arranging the equation, we find the speed

$2gL sin \theta = v^2$

$v=\sqrt{2gL sin \theta}=\sqrt{2(9.8)(3.00)sin 30^{\circ}}=5.42 m/s$

Coefficient of kinetic friction between the floor and the block: 0.3

In the second part of the motion, the block is slowed down by friction along the flat surface. According to the work-energy theorem, the work done by friction is equal to the change in kinetic energy of the block:

$W=\Delta K=K_f -K_i$