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melomori [17]
3 years ago
6

Which of the following fields push on a stationary electron?(A) electric and gravitational fields but not magnetic fields. (B) g

ravitational fields but not electric or magnetic fields. (C) electric, magnetic, and gravitational fields. (D) magnetic and gravitational fields but not electric fields.
Physics
2 answers:
ruslelena [56]3 years ago
8 0

Answer:

(A) electric and gravitational fields but not magnetic fields.

Explanation:

Let's analyze the effect produced by each of the three fields on the stationary electron:

- Gravitational force: the gravitational force exerted on the electron by a gravitational field is

F=mg

where

m is the mass of the electron

g is the strength of the gravitational field

Since the mass of the electron m is non-zero, the electron experiences a gravitational force.

- Electric field: the electric force exerted on the electron by an electric field is

F=qE

where

q is the charge of the electron

E is the magnitude of the electric field

Since the charge q of the electron is non-zero, the electron experiences an electric force.

- Magnetic field: the magnetic force exerted on the electron by a magnetic field is

F=qvBsin \theta

where

q is the electron charge

v is the velocity of the electron

B is the magnitude of the magnetic field

\theta is the angle between the direction of v and B

Since the electron is stationary, we notice that the velocity is zero: v=0, therefore the magnetic force is zero as well.

Therefore, the correct answer is

(A) electric and gravitational fields but not magnetic fields.

Crazy boy [7]3 years ago
8 0

Answer:

Which of the following exists around every object that has mass?

A.

a magnetic field

B.

magnetic poles

C.

a gravitational field

D.

electric charges

Explanation:

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A circuit consists of a series combination of 6.50 −kΩ and 4.50 −kΩ resistors connected across a 50.0-V battery having negligibl
Vlada [557]

Answer:

Part A: 16.1 V

Part B: 20.5 V

Part C: 21.5%

Explanation:

The voltmeter is in parallel with the 4.5-kΩ resistor and the combination is in series with the 6.5-kΩ resistor. The equivalent resistance of the parallel combination is given as

\dfrac{1}{R_E}=\dfrac{1}{4.50}+\dfrac{1}{10.0}

R_E=\dfrac{4.50\times10.0}{4.50+10.0} = 3.10

Part A

The voltmeter reading is the potential difference across the parallel combination. This is found by using the voltage-divider rule.

V_1 = \dfrac{3.10}{3.10+6.50}\times50.0 = \dfrac{3.10}{9.60}\times50.0 = 16.1 \text{ V}

Part B

Without the voltmeter, the potential difference across the 4.5-kΩ resistor is found using the same rule as above:

V_2 = \dfrac{4.50}{4.50+6.50}\times50.0 = \dfrac{4.50}{11.0}\times50.0 = 20.5 \text{ V}

Part C

The error in % is given by

\dfrac{20.5-16.1}{20.5}\times100\% = \dfrac{4.4}{20.5}\times100\% = 21.5\%

4 0
3 years ago
Read 2 more answers
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