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tensa zangetsu [6.8K]
3 years ago
11

A high school physics teacher also happens to be the junior hockey team coach. During a break at practice, the coach asks two pl

ayers to go to the center of the ice with a 10.0-m pole. A 40-kg player is at one end of the pole and a 60-kg player is at the other end. The players then start pulling themselves together by pulling the rod and sliding on the ice as they move along the rod. When the two players meet, what distance will the 60-kg player have moved
Physics
1 answer:
yawa3891 [41]3 years ago
4 0

Answer:

Explanation:

Since no external force acts on the system , centre of mass of two players will remain the same throughout the movement .

Distance of centre of mass is inversely proportional to mass . So centre of mass of the system will be nearer to 60 kg player

Distance of cetre of mass from 60 kg player

= 10 x 40 / (60+40 )

= 4 m

They will meet at centre of mass .

So, 60 kg player will be moving by a distance of 4 m , 40 kg player will be moving by 6 m before they meet .

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astraxan [27]

I have to say, i love this kind of problems.

So, we got the linear acceleration, as we all know, linear the acceleration its, in dimensional units:

[a]=[\frac{distance}{time^2}].

Now, we got the radius

[r] = [distance]

the angular frequency

[\omega] = \frac{1}{s}

and the mass

[m]=[mass].

Now, the acceleration doesn't have units of mass, so it can't depend on the mass of the particle.

The distance in the acceleration has exponent 1, and so does in the radius. As the radius its the only parameter that has units of distance, this means that the radius must appear with exponent 1. Lets write

a \propto r.

The time in the acceleration has exponent -2 As the angular frequency its the only parameter that has units of time, this means that the angular frequency must appear, but, the angular frequency has an exponent of -1, this means it must be squared

a \propto r \omega^2.

We are almost there. If this were any other problem, we would write:

a = A r \omega^2

where A its an dimensionless constant. Its common for this constants to appears if we need an conversion factor. If we wanted the acceleration in cm/s^2, for example. Luckily for us, the problem states that there is no dimensionless constant involved, so:

a = r \omega^2

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Answer:

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