Answer:
1.28 x 10^4 N
Explanation:
m = 1500 kg, h = 450 km, radius of earth, R = 6400 km
Let the acceleration due to gravity at this height is g'
g' / g = {R / (R + h)}^2
g' / g = {6400 / (6850)}^2
g' = 8.55 m/s^2
The force between the spacecraft and teh earth is teh weight of teh spacecraft
W = m x g' = 1500 x 8.55 = 1.28 x 10^4 N
Answer:
most commonly occurs because of the frequent pumping of water from the ground.
Explanation:
Answer:
a)
b)
Explanation:
a) Let's use the constant velocity equation:

- v is the speed of the muon. 0.9*c
- c is the speed of light 3*10⁸ m/s


b) Here we need to use Lorentz factor because the speed of the muon is relativistic. Hence the time in the rest frame is the product of the Lorentz factor times the time in the inertial frame.


v is the speed of muon (0.9c)
Therefore the time in the rest frame will be:



No we use the value of Δt calculated in a)

I hope it helps you!
<span> The box is exerting a force of its weight. So we'll use W=mg (Note: you can use the notation F=ma, doesn't matter since weight IS a force.) We can call g negative since it's directed down towards the earth.
</span>
<span>W = 5kg(-9.8 m/(s^2)) = -49 N
</span>
<span>Thus, the box exerts a force of 49N downwards. </span>