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stepladder [879]
3 years ago
5

Which of the binamials below is a factor of this trinomial x^2+6x+8

Mathematics
2 answers:
jolli1 [7]3 years ago
7 0
X^2+6x+8 = (x+2) (x+4)
faust18 [17]3 years ago
3 0
The two binomials are (x+2)(x+4).
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HELP PLEASE
Fantom [35]

Answer:

Option C

Step-by-step explanation:

You forgot to attach the expression that models the cost of the camping trip during the three days. However, by analyzing the units, the answer can be reached.

The total cost has to be in units of $.

There are two types of costs in the problem:

Those that depend on the number of days ($/day )

Those that depend on the number of students and the number of days ($/(student * day))

If there are 3 days of camping and b students, then you have to multiply the costs that depend on the days by the number of days (3), and the costs that depend on the number of students you have to multiply them by 'b'

So, if the costs that must be multiplied by 'b' are only those that depend on the number of students, the coefficient of b must be:

3 days (Cost of training + Cost of food Miscellaneous expenses :).

Therefore the correct answer is option C:

C. It is the total cost of 3 days per student of Mr. Brown, with training, food and miscellaneous expenses.

The expression that represents the total expense should have a formula similar to this:

y = (3 days) *([\frac{20.dollars}{(day * student)} + \frac{30.dollars}{(student * day)} + \frac{50.dollars}{(student * day)}] b + \frac{200}{day}) + 1050.dollars

y = 3 ($ 100b + $ 200) + $ 1050

3 0
2 years ago
Read 2 more answers
There are 30 students in a year 6 class.
xxMikexx [17]

Answer:

32

Step-by-step explanation:

add

6 0
2 years ago
The n candidates for a job have been ranked 1, 2, 3,…, n. Let X 5 the rank of a randomly selected candidate, so that X has pmf p
Anon25 [30]

Answer:

A. E(x) = 1/n×n(n+1)/2

B. E(x²) = 1/n

Step-by-step explanation:

The n candidates for a job have been ranked 1,2,3....n. Let x be the rank of a randomly selected candidate. Therefore, the PMF of X is given as

P(x) = {1/n, x = 1,2...n}

Therefore,

Expectation of X

E(x) = summation {xP(×)}

= summation {X×1/n}

= 1/n summation{x}

= 1/n×n(n+1)/2

= n+1/2

Thus, E(x) = 1/n×n(n+1)/2

Value of E(x²)

E(x²) = summation {x²P(×)}

= summation{x²×1/n}

= 1/n

3 0
2 years ago
I will take exam tommorrow so, what shall i do the day before start exam to score best mark?​
Digiron [165]

Study. also, i would leave the answer there, but it says i need 20 words to answer so thats why i included this extra bit, but yeah just study.

7 0
2 years ago
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In the game Kazoo, teams lose one point each time they skip a turn. They earn one point each time their team guesses correctly.
enot [183]
If they have -8 points and +6 points, that'd leave them with a total of -2 points.
So the answer is -2.
4 0
2 years ago
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