2. Rubidium
3. Antimony
4. Ytterbium
5. Einsteinium
Answer : The amount of oxygen gas collected are, 0.217 mol
Explanation :
Using ideal gas equation :

where,
P = pressure of gas =
(1 atm = 760 torr)
V = volume of gas = 5 L
T = temperature of gas = 
n = number of moles of gas = ?
R = gas constant = 0.0821 L.atm/mol.K
Now put all the given values in the ideal gas equation, we get:


Thus, the amount of oxygen gas collected are, 0.217 mol
Answer:
(NH4)2Cr2O7
Explanation:
Hope this somehow helped.
Answer:
C₂ = 1.26 mol/dm³
Explanation:
Given data:
Volume of HCl =V₁ = 15.7 cm³
Volume of LiOH = V₂ = 25 cm³
Concentration of HCl =C₁ = 2 mol/dm³
Concentration of LiOH =C₂= ?
Solution:
Chemical equation:
LiOH + HCl → LiCl + H₂O
Formula:
C₁V₁ = C₂V₂
by putting values,
15.7 cm₃× 2 mol/dm³ = C₂× 25 cm³
C₂ = 15.7 cm₃× 2 mol/dm³ / 25 cm³
C₂ = 31.4 cm₃.mol/dm³ / 25 cm³
C₂ = 1.26 mol/dm³