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2 years ago

Sodium (Na) reacts with chlorine gas (Cl2

Chemistry

2 answers:

alisha [4.7K]2 years ago

5 0

Remark

The balance numbers in front of the chemicals tell you how to set up the proportion to solve your question

For every 2 moles Na only 1 mole of Cl2 is required.

Equation

2 moles Na:1 mole Cl2 :: x moles Na:4 moles Cl2

Solution

2/1 = x/4 Cross multiply

2*4 = x*1

8 = x

Conclusion

8 moles of Na will be used. <<< Answer

Studentka2010 [4]2 years ago

3 0

The equation shows that for every mole of Cl2 that react, 2 moles of Na react too. You can find how many moles of sodium react like this:

4 moles Cl2 x (2 moles Na/ 1 mole Cl2) = 8 moles Na

8 moles of Sodium react

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3 years ago

In the laboratory you dissolve 13.9 g of potassium phosphatein a volumetric flask and add water to a total volume of 250mL.

tensa zangetsu [6.8K]

Answer:

Molarity of the solution? 0,262 M.

Concentration of the potassium cation? 0,786 M.

Concentration of the phosphate anion? 0,262 M.

Explanation:

Potassium phosphate (K₃PO₄; 212,27 g/mol) dissolves in water thus:

K₃PO₄ → 3 K⁺ + PO₄³⁻ <em>(1)</em>

Molarity is an unit of chemical concentration given in moles of solute (K₃PO₄) per liters of solution.

There are 250 mL of solution≡0,25 L

The moles of K₃PO₄ are:

13,9 g of K₃PO₄ × $\frac{1mol}{212,27 g}$ = 0,0655 moles of K₃PO₄

The molarity of the solution is:

$\frac{0,0655 moles}{0,25L}$ = 0,262 M

In (1) you can see that 1 mole of K₃PO₄ produces 3 moles of potassium cation. The moles of potassium cation are:

0,0655 moles×3 = 0,1965 moles

The concentration is:

$\frac{0,1965 moles}{0,25L}$ = 0,786 M

The moles of K₃PO₄ are the same than moles of PO₄³⁻, thus, concentration of phosphate anion is the same than concentration of K₃PO₄. 0,262 M

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