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Ksju [112]
2 years ago
15

Help pls what is the (H+) of a solution with a pH of 4?

Chemistry
2 answers:
AfilCa [17]2 years ago
6 0
The answer will be a I’m sure

Answer :A
Natalka [10]2 years ago
4 0

Answer:

A

Explanation:

[H+] = 10^-pH

[H+] = 1 x 10^-4 M

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Write the symbol for every chemical element that has atomic number greater than 3 and atomic mass less than 15.4 u.
mixas84 [53]

Answer:

N, B, Be, C

Explanation:

N (Nitrogen) has 14.0067 B (Boron) has 10.81 Be (Beryllium) has 9 and C (Carbon) has 12

8 0
2 years ago
How many meters are their in one kilometer
tatuchka [14]

There are 1000 meters in 1 Kilometer.

Hope this helps you. :)

5 0
3 years ago
Read 2 more answers
A container with 3.0 moles of gas has a volume of 60.0L with a temperature at 400.K what is the pressure
iris [78.8K]

Answer: P= 1.64 atm

Explanation: solution attached.

Use Ideal gas law

PV= nRT

Derive for P

P= nRT/V R= 0.08205 L.atm/mol.K

Substitute the values.

3 0
3 years ago
Boiling occurs when molecules being changed from liquid to gas plz tell me the answer true or false
Valentin [98]

Answer:

Liquid to Gas

Explanation:

The particles need energy to rise and over come the attractions between them as the liquid gets warmer more particles have sufficient, energy to escape from liquid. eventually even particles in the middle of the liquid form bubbles of gas in the liquid At this point the liquid is boiliing and turning into gas.

5 0
3 years ago
how many grams of calcium chloride can be prepared from 60.4 G of calcium oxide and 69.0 G of hydrochloric acid and a double dis
Ksenya-84 [330]
Balanced equation: 
<span>CaO + 2 HCl --> CaCl2 + H2O </span>
<span>Calculate moles of each reactant: </span>
<span>60.4 g CaO / 56.08 g/mol = 1.08 mol CaO </span>
<span>69.0 g HCl / 36.46 g/mol = 1.89 mol HCl </span>

<span>Identify the limiting reactant: </span>
<span>Moles CaO needed to react with all HCl: </span>
<span>1.89 mol HCl X (1 mol CaO / 2 mol HCl) = 0.946 mol CaO </span>
<span>Because you have more CaO than that available, HCl is the limiting reactant. </span>

<span>Calculate moles and mass CaCl2: </span>
<span>1.89 mol HCl X (1 mol CaCl2 / 2mol HCl) X 111.0 g/mol = 105 g CaCl2</span>
8 0
2 years ago
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