Answer :
is the oxidizing agent and Fe is the reducing agent.
Explanation :
Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.
Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.
The balanced redox reaction is :

The half oxidation-reduction reactions are:
Oxidation reaction : 
Reduction reaction : 
In order to balance the electrons, we multiply the oxidation reaction by 4 and reduction reaction by 3 then added both equation, we get the balanced redox reaction.
Oxidation reaction : 
Reduction reaction : 

In this reaction,
is the reducing agent that loses an electron to another chemical species in a redox chemical reaction and itself gets oxidized and
is the oxidizing agent that gain an electron to another chemical species in a redox chemical reaction and itself gets reduced.
Thus,
is the oxidizing agent and Fe is the reducing agent.
Answer:
a. True
b. True
c. False
d. True
Explanation:
a). A a very low substrate concentration ,
. Thus according to the Machaelis-Menten equation becomes
![$V_0 = \frac{V_{max} \times [S]}{Km}$](https://tex.z-dn.net/?f=%24V_0%20%3D%20%5Cfrac%7BV_%7Bmax%7D%20%5Ctimes%20%5BS%5D%7D%7BKm%7D%24)
Here since the
varies directly to the substrate concentration [S], the initial velocity is lower than the maximal velocity. Thus option (a) is true.
b). The Michaelis -Menten kinetics equation states that :
![$V_0 = \frac{V_{max} \times [S]}{Km+[S]}$](https://tex.z-dn.net/?f=%24V_0%20%3D%20%5Cfrac%7BV_%7Bmax%7D%20%5Ctimes%20%5BS%5D%7D%7BKm%2B%5BS%5D%7D%24)
Here the initial velocity changes directly with the substrate concentration as
is directly proportional to [S]. But
is same for any particular concentration of the enzymes. Thus, option (b) is true.
c). As the substrate concentration increases, the initial velocity also increases. Thus option (c) is false.
d). Option (d) explains the procedures to estimate the initial velocity which is correct. Thus, option (d) is true.
Answer:

Explanation:
The amount adsorbed (solute) is the acetic acid, and the adsorbent is the activated charcoal. The mass of the adsorbent is 10 g.
So, we need to calculate the mass of the acetic acid as follows:

Where:
n: is the number of moles = C*V
M: is the molecular mass = 60.052 g/mol
C: is the final concentration of the acid = 0.5*0.2 mol/L = 0.10 mol/L
V: is the volume = 50 ml = 0.050 L

Now, the amount of solute adsorbed per gram of the adsorbent is:

Therefore, the amount of solute adsorbed per gram of the adsorbent is 0.03 g/g.
I hope it helps you!