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3 years ago

A general term for a chemical which accelerates a reaction without becoming chemically involved is called a ______.

Chemistry

1 answer:

AleksAgata [21]3 years ago

6 0

Answer:

Catalyst

Explanation:

A general term for a chemical which accelerates a reaction without becoming chemically involved is called a catalyst.

Catalysts are used in industrial processes to speed up the rate of a chemical reaction. For instance, in the Contact process used in the production of sulphuric (vi) acid, vanadium(V) oxide (V2O5) is used as a catalyst to speed up the production of the acid. Vanadium(V) oxide (V2O5) is preferred to Platinum which was initially used as the catalyst since it does not react with any of the products of the process

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3 years ago

Based on the results from this experiment, predict whether some of the following combinations of compounds would precipitate or

iren [92.7K]

Answer:

* No precipitate: $LiOH(aq)+NaCl(aq)\rightarrow LiCl(aq)+NaOH(aq)$

* Precipitate: $3BaCl_2(aq) +2Na_3PO_4(aq) \rightarrow Ba_3(PO_4)_2(s)+6NaCl(aq)$

* Precipitate: $MgSO_4(aq)+2KOH(aq)\rightarrow Mg(OH)_2(s)+K_2SO_4(aq)$

Explanation:

Hello!

In this case, since these all are double displacement reactions, in which the cations and anions are exchanged, we can write the resulting chemical reactions as follows:

a. LiOH and NaCl: No precipitate is formed since LiOH and NaOH are both largely soluble in water:

$LiOH(aq)+NaCl(aq)\rightarrow LiCl(aq)+NaOH(aq)$

b. BaCl2 and Na3PO4: barium phosphate precipitate is formed because it has a large molar mass which makes it insoluble in water:

$3BaCl_2(aq) +2Na_3PO_4(aq) \rightarrow Ba_3(PO_4)_2(s)+6NaCl(aq)$

c. MgSO4 and KOH: magnesium hydroxide "milky" precipitate is formed because it is not soluble in water:

$MgSO_4(aq)+2KOH(aq)\rightarrow Mg(OH)_2(s)+K_2SO_4(aq)$

Moreover, we can relate the solubility of a substance by considering its polarity, molar mass and nature; usually, heavy substances tend to be insoluble in water as well as nonpolar compounds.

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3 years ago

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Answer:

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4 years ago