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kolbaska11 [484]
3 years ago
8

A general term for a chemical which accelerates a reaction without becoming chemically involved is called a ______.

Chemistry
1 answer:
AleksAgata [21]3 years ago
6 0

Answer:

Catalyst

Explanation:

A general term for a chemical which accelerates a reaction without becoming chemically involved is called a catalyst.

Catalysts are used in industrial processes to speed up the rate of a chemical reaction. For instance, in the Contact process used in the production of sulphuric (vi) acid, vanadium(V) oxide (V2O5) is used as a catalyst to speed up the production of the acid. Vanadium(V) oxide (V2O5) is preferred to Platinum which was initially used as the catalyst since it does not react with any of the products of the process

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Which refers to the force that one massive object exerts to attract another object? velocity gravity acceleration newton
Dmitry_Shevchenko [17]

Answer:

gravity is the correct answer to the given question .

Explanation:

The gravity is the gravitational force due to the gravitational the solar system as well as the other body of dimensional object to its center point. The gravitational force maintains all the planetary systems in the orbit over the sun.We can called gravitational force as the universal force .

  • The gravitational force attracts the huge object for grabbing the another object.
  • All the other option are not attracting the another object that's why these are incorrect option .
5 0
3 years ago
Read 2 more answers
Which are examples of biotic factors? Select three options.
alina1380 [7]

The biotic factors are bacteria soil, dead leaves, and stream water.

<h3>What is an abiotic factor?</h3>

An abiotic factor is a non-living part of an ecosystem that shapes its environment.

Biotic and abiotic factors make up a community via interaction.

Biotic factors are considered living things (having "life") while abiotic factors are simply non-living things.

The dead leaves of plants are an abiotic factor, the bacteria in soil are living matter and stream flowing, etc.

Hence, the biotic factors are bacteria soil, dead leaves, and stream water.

Learn more about the abiotic factor here:

brainly.com/question/12689972

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6 0
1 year ago
How many micrograms (ug) are in 3.4 x 10^-5 ounces (oz)
marysya [2.9K]

Answer:

964ug

Explanation:

The problem here involves converting from one unit to another.

 We are to convert from ounces to micrograms.

                                    1ug  = 1 x 10⁻⁶g

                                    1oz  = 28.35g

       

So we first convert to grams from oz then take to ug:

 Solving:

                    1oz  = 28.35g

             3.4 x 10⁻⁵oz  will then give  3.4 x 10⁻⁵ x 28.35 = 9.64  x 10⁻⁴g

So;

                    1 x 10⁻⁶g    = 1ug

          9.64  x 10⁻⁴g will give \frac{9.64 x 10^{-4} }{1 x 10^{-6} }      = 9.64 x 10²ug or 964ug

8 0
2 years ago
1. Calculate the [H] in a solution that has a pH of 9.88.
Olenka [21]
The answer to the question is D.
5 0
3 years ago
Read 2 more answers
A 100.0-mL sample of 1.00 M NaOH is mixed with 50.0 mL of 1.00 M H2SO4 in a large Styrofoam coffee cup calorimeter fitted with a
worty [1.4K]

Answer:

THE ENTHALPY CHANGE IN KJ/MOLE IS +114 KJ/MOLE.

Explanation:

Heat = mass * specific heat capacity * temperature rise

Total volume = 100 + 50 = 150 mL

Total mass = density * volume

Total mass = 1 * 150 mL = 150 g

So therefore, the heat evolved during the reaction is:

Heat = 150 * 4.18 * ( 31.4 - 22.3)

Heat = 150 * 4.18 * 9.1

Heat = 5705.7 J

Equation for the reaction:

2 NaOH(aq) + H2SO4(aq) → Na2SO4(aq) + 2 H2O(l)  

From the equation, 2 moles of NaOH reacts with 1 mole of H2SO4 to produce 1 mole of Na2SO4 and 2 moles of water

50 mL of 1 M of H2SO4 contains

50 * 1 / 1000 mole of acid

= 0.05 mole of acid

The production of 1 mole of water evolved 5705.7 J of heat and hence the enthalpy changein kJ per mole will be:

0.05 mole of H2SO4 produces 5705.7 J of heat

1 mole of H2SO4 will produce 5705.7 / 0.05 J

= 114,114 J / mole

In kj/mole = 114 kJ/mole.

Hence, the enthalpy change of the reaction in kJ /mole is +114 kJ/mole.

5 0
3 years ago
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