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Juli2301 [7.4K]
3 years ago
11

An alpha particle has the same composition as a A) hydrogen nucleus B) deuterium nucleus C) beryllium nucleus D) helium nucleus​

Chemistry
1 answer:
Elza [17]3 years ago
4 0

Answer:

Helium Nucleus

Explanation:

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If 45.0 liters of oxygen is measured at 24.0C, what would be its volume at standard temperature?
nika2105 [10]

The volume of the oxygen gas at standard temperature  is 41.36 liters.

The given parameters;

  • <em>initial volume of oxygen, V₁ = 45 L</em>
  • <em>temperature of oxygen, T₁ = 24 ⁰C = 297 K</em>
  • <em>standard temperature, T₂ = 0 ⁰C = 273 K</em>

<em />

The volume of the oxygen gas at standard temperature is determined by applying Charles law as shown below;

\frac{V_1}{T_1} = \frac{V_2}{T_2} \\\\V_2 = \frac{V_1 T_2}{T_1} \\\\V_2 = \frac{45 \times 273}{297} \\\\V_2 = 41.36 \ L

Thus, the volume of the oxygen gas at standard temperature  is 41.36 L.

Learn more here:brainly.com/question/16927784

6 0
3 years ago
What evidence exists that science is dynamic, that scientific theories are frequently modified?
almond37 [142]

Answer:

Nonetheless, scientific change is connected with many other key issues in philosophy of science and broader epistemology, such as realism, rationality and relativism. The present article does not attempt to address them all. Higher-order debates regarding the methods of historiography or the epistemology of science, or the disciplinary differences between History and Philosophy, while important and interesting, represent an iteration of reflection on top of scientific change itself, and so go beyond the article’s scope.

Explanation:

8 0
4 years ago
a 100g sample of material requires 5104.5 joules of heat energy to raise its temperature from 20 degrees Celsius to 80 degrees C
levacccp [35]

Answer: 0.85075J/g.K

Explanation:

Mass of the material = 100g

Energy (Q) = 5104.5J

T1 = 20°C = 293K

T2 = 80°C = 353K

Formula for heat energy (Q) = mc ∇T

Q = mc∇T

∇T = T2 - T1

∇T = 353K - 293K = 60K

Q = mc∇T

C = Q / m∇T

C = (5104.5) / (100 * 60)

C = 0.85075 J/gK

The specific heat capacity of the material is 0.85075J/gK.

5 0
4 years ago
Read 2 more answers
Phosphoric acid is a triprotic acid ( K a1 = 6.9 × 10 − 3 Ka1=6.9×10−3, K a2 = 6.2 × 10 − 8 Ka2=6.2×10−8, and K a3 = 4.8 × 10 −
irina1246 [14]

<u>Answer:</u> To calculate the pH of the buffer composed of H_2PO_4^-\text{ and }HPO_4^{-2}, we use the K_a2

<u>Explanation:</u>

Phosphoric acid is a triprotic acid and it will undergo three dissociation reaction each having their respective dissociation constants.

The chemical equation for the first dissociation reaction follows:

H_3PO_4\rightleftharpoons H_2PO_4^-+H^+;K_a1=6.9\times 10^{-3}

The chemical equation for the second dissociation reaction follows:

H_2PO_4^-\rightleftharpoons HPO_4^{2-}+H^+;K_a2=6.2\times 10^{-8}

The chemical equation for the third dissociation reaction follows:

HPO_4^{2-}\rightleftharpoons PO_4^{3-}+H^+;K_a3=4.8\times 10^{-13}

To form a buffer composed of H_2PO_4^-\text{ and }HPO_4^{-2}, we use the K_a of second dissociation process

To calculate the pK_a, we use the equation:

pK_a=-\log (K_a)\\\\pK_a=-\log(6.2\times 10^{-8})\\\\pK_a=7.21

To calculate the pH of buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a2+\log(\frac{[\text{conjugate base}]}{[\text{weak acid}]})

pH=pK_a2+\log(\frac{[HPO_4^{2-}]}{[H_2PO_4^-]})

We are given:

pK_a2 = negative logarithm of second acid dissociation constant of phosphoric acid = 7.21

[HPO_4^{2-}] = concentration of conjugate base

[H_2PO_4^{-}] = concentration of weak acid

Hence, to calculate the pH of the buffer composed of H_2PO_4^-\text{ and }HPO_4^{-2}, we use the K_a2

3 0
4 years ago
1.Complete and balance each of the acid base neutralizations below. Identify the spectator ions.
Natalka [10]

Answer:

can you give me some hint

4 0
2 years ago
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