<span>Answer:
2 C8H18 + 25 O2 => 16 CO2 + 18 H2O
1.0 kg = 1000 g C8H18 = 1000 g / 114.2293 g/mole = 8.75 moles C8H18
8.75 moles C8H18 produce (16/2) (8.75) = 70 moles CO2
70 moles CO2 = (70 moles) (44.0096 g/mole) = 3081 g CO2 = 3.1 kg CO2</span>
If your collecting at STP, you can use the converting constant of 22.4 litters/ One Mole. So, you would have convert ml to L and then go from there.
Also, when working with grams, you usually need to know the gas your working with. As one mole equals the atomic mass of an element in grams.
Could you show a picture of the question so I could answer?
I actually couldn't guess at first what the question is. But looking closely at the statements, I deduced that some are correct and some are not. So, I think this is a true or false problem. So,
<span>The 1s orbital(s) do(es) not have any nodes. - This is false. Nodes are the planes that the orbitals do not fill. The formula for the number of nodes is:
N = n - l
where
n is the energy level
l is 0 for s subshell, 1 for p subshell, 2 for d subshell, 3 for f subshell; l also signifies the number of angular nodes.
Thus,
N = 1 - 0 = 1 node
</span><span>The 1s orbital(s) has(have) a node at the nucleus. Since this is the opposite of the first statement, this is true.
</span><span>The 3d orbital(s) has(have) a cloverleaf shape, with four lobes of electron density around the nucleus and two perpendicular nodal planes.
This is true. The shape of d subshell is cloverleaf, and all have four lobes. Since l=2, there are 2 perpendicular or angular nodes.
</span><span>The f orbitals are even more complex. This is true. The f subshell is the last subshell. It has complex shapes and it rarely comes up in chemistry.
</span><span><em>The number of nodes (and nodal planes) depends on the specific orbital, but there will be more than for s, p, or d orbitals. </em><em />This is false. In fact, f orbitals have more nodes because l = 3. That means they always have 3 angular nodes, which is greater than the other subshells.</span>
You can answer that by looking at how much water got remained atop. The more water atop means less permeability. If something is permeable it let the water diffuse. So the answer is silt.
