Answer:
C₂H₂O₃
Explanation:
The empirical formula of a compound is derived bu finding the whole ratios of the constituent elements.
In succinic acid, the ratios of carbon to hydrogen to oxygen is calculated as follows:
<u>% mass</u>
Carbon- 40.60
Hydrogen - 5.18
Oxygen - 54.22
<u>RAM</u>
Carbon -12
Oxygen - 15.994
Hydrogen -1.008
<u>No of moles elements in the compound</u>
Carbon = 40.60/12=3.3833
Oxygen = 54.22/15.994= 3.39
Hydrogen= 5.18/1.008 = 5.1389
Mole ratios of the individual elements we divide by the smallest value of the number of moles.
Carbon: Hydrogen : Oxygen
3.3833/3.3833:3.39/3.3833:5.1389/3.3833
=1:1:1.5
We can multiply the value by 2 to get the whole number ratio.
=2:2:3
The empirical formula will be:
C₂H₂O₃
Answer:
As the frequency increases, the wavelength decreases. ... (a) For a given sound, as the temperature increases, what happens to the frequency? There is no change in frequency. The speed of sound increases by about 0.5 m/s for each degree Celsius when the air temperature rises.
Answer:
2
Explanation:
CO₂ shows that there are 2 oxygen molecules. Also, the name Carbon Dioxide. This shows there is One Carbon and Two Oxygen molecules from the naming system.
Answer: 195.3 K
Explanation: Use Charles Law to get T2
Charles Law V1 / T1 = V2 / T2
Derive the equation to find T2
T2 = V2T1 / V1
Convert temperature into K
T1 = 20.0 °C + 273 = 293 K
Substitute the values:
4.00 L x 293 K / 6.00 L = 195. 3 K
Answer:
(3) 5.36
Explanation:
Since this is a titration of a weak acid before reaching equivalence point, we will have effectively a buffer solution. Then we can use the Henderson-Hasselbalch equation to answer this question.
The reaction is:
HAc + NaOH ⇒ NaAc + H₂O
V NaOH = 40 mL x 1 L/1000 mL = 0.040 L
mol NaOH reacted with HAc = 0.040 L x 0.05 mol/L = 0.002 mol
mol HAC originally present = 0.050 L x 0.05 mol/L = 0.0025 mol
mol HAc left after reaction = 0.0025 - 0.002 = 0.0005
Now that we have calculated the quantities of the weak acid and its conjugate base in the buffer, we just plug the values into the equation
pH = pKa + log ((Ac⁻)/(HAc))
(Notice we do not have to calculate the molarities of Ac⁻ and HAc because the volumes cancel in the quotient)
pH = -log (1.75 x 10⁻⁵) + log (0.002/0.0005) = 5.36
THe answer is 5.36
