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salantis [7]
3 years ago
10

How many electrons are in 1 mole of carbon atoms?

Chemistry
1 answer:
Mkey [24]3 years ago
7 0

Answer:

6 electrons

Explanation:

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How do you find the molar mass of a compound?
kobusy [5.1K]

Answer:The molar mass of a compound cab be find by adding up all the molar mass of the element present in the compound... Check the image for more clarification

Explanation:

8 0
3 years ago
what noble gas has the same electron configuration as each of the ions in the following compounds? a. Cesium sulfide b. strontiu
saveliy_v [14]

Answer:

A. Cesium sulfide

Explanation:

looked it up lol

7 0
3 years ago
the problem say what is the volume (in kL) of 3.7505 x 10^4 mg of iron? Iron has a density of 7.87 g/ml. Use correct significant
Elis [28]
So first find the volume

so 7.78g/ml and (3.7505 times 10^4) grams
therefor we dividde (3.7505 times 10^4) by 7.78 and get how many ml

the answer is 4820.69 ml

kL means kilo lieters
kilo=1000
kL=1000Liters
ml=milileters=1/1000 leiter
1000ml=1L
therfor
1kL=1000L
1000L=1000 times (1000ml)
1000L=1,000,000ml
1kL=1,000,000ml

so to convert to kL divide 4820.69 by 1,000,000
0.00482069
convert to scientifiic notation
4.8 times 10^-3

the answer is 4.8 times 10^-3 kL

4 0
3 years ago
What is the oxidation state of Hydrogen in H20<br><br> +2<br> +1<br> -2<br> -1
xeze [42]
<h3>What is the oxidation number of oxygen in H2O?</h3>

Oxygen almost always has an oxidation number of -2, except in peroxides (H 2 O 2) where it is -1 and in compounds with fluorine (OF 2) where it is +2. Hydrogen has an oxidation number of +1 when combined with non-metals, but it has an oxidation number of -1 when combined with metals.

<h3><em>Sure hoep this helps you :)</em></h3>
6 0
2 years ago
A sample of oxygen gas has a volume of 45.8 mL when its pressure is 0.492 atm. What
White raven [17]

Answer:

<h2> a. 23.6</h2>

Explanation:

P_1=0.492\:atm\\V_1 = 45.8\:ml\\V_2 = ?\\P_1 = 0.954\:atm\\\\Boyle's Law = P_1V_1 = P_2V_2\\\\Lets \:make\: V \:subject\:of\:the\:formula\\\\\frac{P_1V_1}{P_2} = \frac{P_2V_2}{P_2} \\ \\V_2 =\frac{P_1V_1}{P_2} \\V_2 = \frac{0.492\times45.8}{0.954}\\ \\V_2 = \frac{22.5336}{0.954} \\\\V_2  = 23.620\\\\V_2 = 23.6

4 0
3 years ago
Read 2 more answers
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