Answer:
Lindsey biked 45 miles for 3 hours at 15 mph and walked 8 miles for 2 hours at 4 mph.
Explanation:
Speed = distance/time
Let the distance that Lindsey biked through be x miles and the time it took her to bike through that distance be t hours
Then, the rest of the distance that she walked is (53 - x) miles
And the time she spent walking that distance = (5 - t) hours
Her biking speed = 15 mph = 15 miles/hour
Speed = distance/time
15 = x/t
x = 15 t (eqn 1)
Her walking speed = 4 mph = 4 miles/hour
4 = (53 - x)/(5 - t)
53 - x = 4 (5 - t)
53 - x = 20 - 4t (eqn 2)
Substitute for X in (eqn 2)
53 - 15t = 20 - 4t
15t - 4t = 53 - 20
11t = 33
t = 3 hours
x = 15t = 15 × 3 = 45 miles.
(53 - x) = 53 - 45 = 8 miles
(5 - t) = 5 - 3 = 2 hours
So, it becomes evident that Lindsey biked 45 miles for 3 hours at 15 mph and walked 8 miles for 2 hours at 4 mph.
Answer:
a)T= mg/2
b) T = 31. 88 N
c)Tension will increase
Explanation:
Given that m= 6.5 Kg
a)
The force due to gravity = m g
The tension in the chain = T
The total tension = 2 T
By balancing force in vertical direction
2 T = m g
T= mg/2
b)
2 T = m g
2 x T = 6.5 x 9.81
T = 31. 88 N
c)
Lets take angle made by chain is θ
So the total tension in vertical direction = 2 T cos θ
2 T cos θ = m g
T= mg/(2cos θ)
It means that tension will increase because cos θ is always less than 1.
First, since the echo frequency is greater, the car must be roaming
to the police car.
This is for the reason that the car is "running over" its own wave
fronts, creating the wavelengths tinier, and henceforth increasing the
frequency.
The trick here is to understand that the relative speed between the cars is
half of the speed of the echo for the reason that the echo is returning to the
police car at the similar speed as the sound wave trips to the moving
car.
It would also appear that the speed of sound has been expected to be 337
m/s
So if v is the moving car's velocity, the correct formula to use is:
2v / 337 = (1250/1200) - 1
2v = 14.04 m/s
v = 7.02 m/s
1. Radio waves are generated by a transmitter and detected by a reciever. The reciever then encodes the radio wave into information to transport into your radio. You may have listened to either AM or FM radio.
2. Cell phones creates up and down sounds with the microphone. The microchip inside the phone turns those up and down sounds into numbers, and sends it off to the cell tower. The cell tower processes those numbers and sends it off to the phone you are trying to call.
3. The television service delivers programming to viewers by relaying information to communications satellites that can be found orbiting the earth. The satellite receiver decodes the programming to the viewer’s TV.
Answer:
The first eagle hear a frequency of 4.23kHz and the second eagle hear a frequency of 3.56kHz
Explanation:
Given that
both eagle are flying towards one another
speed of the first eagle v1 = 15m/s
speed of the second eagle v2 = 20m/s
frequency emitted by the first eagle f1= 3200Hz
frequency emitted by the second eagle f2 = 3800Hz
speed of sound v = 330m/s
the second part
The first eagle hear a frequency of 4.23kHz and the second eagle hear a frequency of 3.56kHz
