Answer: 134.23g at 0° (horizontal) and 77.5g at 90° (vertical).
Explanation:
1) Since the mass of <span>155 g is suspended at 210 degrees, you need to find the components of its weight on the orthogonal coordinate system (0° and 90°).
</span>
<span>2) You do that using the trignometric ratios sine and cosine.
</span>
<span>Weight is mass × g.
</span>
<span>Weight of the object = 155g × g
</span>
<span>Angle, α = 210°
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<span>Horizontal component (0°)
</span>
<span>cosα = horizontal / hypotenuse ⇒ horizontal = hypotenuse × cosα
</span>
⇒ horizontal = 155g × g × cos(210°) = - 134.23g × g
Vertical component
sinα = vertical / hypotenuse ⇒ vertical = hypotenuse × sinα
⇒ vertical = 155g × g × sin(210°) = -77.5g × g
3) Conclusion:
Therefore, the masses that must be suspended to balance the forces of the 155g mass are 134.23g at 0° (horizontal) and 77.5g at 90° (vertical).
To solve this problem we will apply the concepts related to the kinematic equations of linear motion. From there we will define the distance as the circumference of the earth (approximate as a sphere). With the speed given in the statement we will simply clear the equations below and find the time.
The circumference of the earth would be
Velocity is defined as,
Here 
, then
Therefore will take 167463.97 s or 1 day 22 hours 31 minutes and 3.97seconds
-- Top picture:
'a' and 'b' have the same magnitude, and both are positively charged.
-- Bottom picture:
The charge on the particle is negative.
Answer:
You are correct. Cold water sinks in warm or room temperature water.
A camera is a motor.
A drill is a motor.
A hand-squeeze flashlight is a generator.
Hope this helped :)
