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Helen [10]
3 years ago
5

An empty 25.00 mL volumetric flask has a mass of 20.550 g. When it is partially filled with metal pellets, the mass is 130.278 g

. The flask is then filled to the mark with methanol (density = 0.7918 g/mL), and the total mass of the flask, metal, and methanol is 142.419 g. Calculate the density of the metal pellets
Chemistry
2 answers:
NeTakaya3 years ago
6 0

Answer:

11.347 g/mL is the density of the metal pellets.

Explanation:

The total mass of the flask, metal, and methanol  = M = 142.412 g

Mass of flask = 25.00 mL

Mass of flask and metal pellets = 130.278 g

mass of flask + mass of pellets = 130.270 g

M = mass of flask + mass of pellets + mass of methanol

142.412 g = 130.270 g + mass of methanol

Mass of methanol = 12.142 g

Volume of methanol = v

Density of the methanol = 0.7918 g/mL

v=\frac{ 12.142 g}{ 0.7918 g/mL}=15.33 mL

Volume of the flask = V = 25 mL

Volume of the pellets = V'

V = V' + v

V'= V - v = 25 mL - 15.33 mL = 9.67 mL

Density of the metal pellets = d

Mass of the metal pellets = m

Mass of flask and metal pellets = 130.278 g

20.55 g + m = 130.278 g

m = 109.728 g

d=\frac{m}{V'}=\frac{ 109.728 g}{9.67 mL}=11.347 g/mL

11.347 g/mL is the density of the metal pellets.

nasty-shy [4]3 years ago
3 0
<span>Density is a value for mass, such as kg, divided by a value for volume, such as m^3. Density is a physical property of a substance that represents the mass of that substance per unit volume. We calculate as follows:

Density = (130.278 - 20.550) / (142.419 - 130.278)/0.7918 = 7.16 g/mL</span>
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Firlakuza [10]

Answer:

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Explanation:

Step 1: Given data

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  • Final volume (Vf): 100.0 L

Step 2: Calculate the work (w) done by the gaseous mixture

We will use the following expression.

w = -P × ΔV = -P × (Vf - Vi)

w = -27.0 atm × (100.0 L - 88.0 L)

w = -324 atm.L

Step 3: Convert w to Joule (SI unit)

We will use the conversion factor 1 atm.L = 101.325 J.

-324 atm.L × 101.325 J/1 atm.L = -3.28 × 10⁴ J

5 0
3 years ago
If the molecule could move upward without colliding with other molecules, then how high would it go before coming to rest? Give
tankabanditka [31]

The maximum height at which nitrogen molecule will go before coming to rest is 14 kilometers.

Given:

The nitrogen gas molecule with a temperature of 330 Kelvins is released from Earth's surface to travel upward.

To find:

The maximum height of a nitrogen molecule when released from the Earth's surface before coming to rest.

Solution:

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  • The temperature of nitrogen gas particle = T = 330 K

The average kinetic energy of the gas particles is given by:

K.E=\frac{3}{2}K_bT\\\\K.E=\frac{3}{2}\times 1.38\times 10^{-23} J/K\times 330 K\\\\K.E=6.381\times 10^{-21} J

The nitrogen molecule at its maximum height will have zero kinetic energy as all the kinetic energy will get converted into potential energy

  • The potential energy at height h = P.E = 6.381\times 10^{-21} J
  • Molar mass of nitrogen gas =  28.0134 g/mol
  • Mass of nitrogen gas molecule = m

m= \frac{ 28.0134 g/mol}{6.022\times 10^{23} mol^{-1}}=4.652\times 10^{-23} g\\\\1g=0.001kg\\\\m=4.652\times 10^{-23}\times 0.001 kg\\\\=4.652\times 10^{-26} kg

  • The acceleration due to gravity = g = 9.8 m/s^2
  • The maximum height attained by nitrogen gas molecule = h
  • The potential energy is given by:

P.E=mgh

6.381\times 10^{-21} J=4.652\times 10^{-26} kg\times 9.8 m/s^2\times h\\\\h=\frac{6.381\times 10^{-21} J}{4.652\times 10^{-26} kg\times 9.8 m/s^2}\\\\h=13,996.6 m\\\\1 m = 0.001 km\\\\h=13,996.6 m=h=13,996.6\times 0.001 k m\\\\=13.9966 km \approx 14 km

The maximum height at which nitrogen molecule will go before coming to rest is 14 kilometers.

Learn more about the average kinetic energy of gas particles here:

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brainly.com/question/6329137?referrer=searchResults

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The pressure of nitrogen gas at 35°C is changed from 0.89 atm to 4.3 atm. What will be its final temperature in Kelvin?
Alja [10]

Answer: The final temperature in Kelvin is 1488

Explanation:

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

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P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

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Putting values in above equation, we get:

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Hence, the final temperature in Kelvin is 1488

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