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2 years ago

Help with this please!!

Chemistry

2 answers:

Natali5045456 [20]2 years ago

6 0

Answer:

#2 is melting ice and #3 is radiation

Explanation:

hope this helped

-BARSIC- [3]2 years ago

5 0

Answer for number two it’s C for number three it’s D

Explanation:

just pay attention next time and you wouldn’t have to ask

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What is the molar mass of Aluminum chromate

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Al2(CrO4)3 = 401.9 grams per mole

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3 years ago

Suzie Q wants to know the effect of different colors of light on the growth of plants. She believes that plants can survive best

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Answer:

growth of plants

Explanation:

The variable which changes on its own is called the independent variable and the variable which changes according to the changes in the independent variable is called the dependent variable.

Here the growth of the plants is observed under light of different colors. So, Suzie is has placed 5 ferns and placed them under different color lights. She also keeps the other factors such as amount of water the plants receive the same. She measures the different color lights have on growth of the plants.

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2 years ago

A can of hairspray is crushed down to half its normal volume. What will

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Answer:

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Explanation:

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2 years ago

A dilute solution of bromine in carbon tetrachloride behaves as an ideal-dilute solution. The vapour pressure of pure CCl4 is 33

ANEK [815]

Explanation:

The given data is as follows.

Vapour pressure of pure $CCl_{4}$ = 33.85 Torr

Temperature = 298 K

Mole fraction of $Br_{2}$ = 122.36 torr

Therefore, calculate the vapor pressure of $Br_{2}$ as follows.

Vapour pressure of $Br_{2}$ = mole fraction of $Br_{2}$ x K of $Br_{2}$

= 0.050 x 122.36 Torr

= 6.118 Torr

So, vapor pressure of $Br_{2}$ is 6.118 Torr .

Now, calculate the vapor pressure of carbon tetrachloride as follows.

Vapour pressure of $CCl_{4}$ = mole fraction of $CCl_{4}$ x Pressure of $CCl_{4}$

= (1 - 0.050) × 33.85 Torr

= 32.1575 Torr

So, vapor pressure of $CCl_{4}$ is 32.1575 Torr .

Hence, the total pressure will be as follows.

= 6.118 Torr + 32.1575 Torr

= 38.2755 Torr

Therefore, composition of $CCl_{4}$ = $\frac{32.1575 Torr}{38.2755 Torr}$

= 0.8405

Composition of $CCl_{4}$ is 0.8405 .

And, composition of $Br_{2}$ = $\frac{6.118 Torr}{38.2755 Torr}$

= 0.1598

Composition of $Br_{2}$ is 0.1598 .

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