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2 years ago

11

The internet is a local communication network that allows only certain computers to connect and exchange information True or fal

se

1 answer:

choli [55]2 years ago

6 0

False, the internet branches throughout many countries connecting you to the rest of the world from home. Hope it helped!

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Use bond energies from Table 10.3 in the textbook to estimate the enthalpy change (ΔH) for the following reaction. C2H2(g)+H2(g)

Digiron [165]

Answer: $=176.6kJmol^{-1}$

Explanation:Bond energy of H-H is 436.4 kJ/mole

Bond energy of C-H is 414 kJ/mol

Bond energy of C=C is 620 kJ/mol

Bond energy of C≡C is 835 kJ/mol

$\Delta H= {\text {sum of bond energies of reactants}}- {\text {sum of bond energies of products}}$

$\Delta H$ = {1B.E(C≡C)+2B.E(C-H) +1B.E(H-H)} - {1B.E(C=C)+4B.E(C-H)}

$\Delta H= {1B.E(835kJmole^{-1})+2B.E(414kJmole^{-1}) +1B.E(436.4kJmole^{-1})} - {1B.E(620kJmole^{-1})+4B.E(414kjmole^{-1})}$

$=176.6kJmol^{-1}$

7 0

3 years ago

If 22.5L of nitrogen at 748 mm Hg are compressed to 725 mm Hg at constant temperature. What is the new volume?2.A gas with a vol

kykrilka [37]

Answer:

a)23.2 L

b)68.3kPa

c)7.5 atm

d)60.5L

e)1.67 atm

Explanation:

From Boyle's law:

P1V1=P2V2

P1= 748mmHg

P2=725mmHg

V1= 22.5L

V2??

V2= P1V1/P2= 748×22.5/725= 23.2 L

b)

V1=4.0L

P1= 205×10^3Pa

V2= 12.0L

P2=???

P2= P1V1/V2= 205×10^3×4/12

P2= 68.3×10^3 Pa or 68.3kPa

c)

P1= 1 atm

V1= 196.0L

P2= ??

V2= 26.0L

P2= P1V1/V2=1×196.0/26.0

P2= 7.5 atm

d)

V1= 40.0L

P1= 12.7×10^3Pa

V2=???

P2= 8.4×103Pa

V2= P1V1/P2= 12.7×10^3×40.0/8.4×103

V2=60.5L

e)

V1= 100mL

P1= 1atm

V2= 60mL

P2=???

P2= P1V1/V2= 1×100/60

P2= 1.67 atm

4 0

2 years ago

Identify the number of moles in 369 grams of calcium hydroxide. Use the periodic table and the polyatomic ion resource.

topjm [15]

Answer : The number of moles in 369 grams of calcium hydroxide is, 4.98 moles

Explanation : Given,

Mass of calcium hydroxide = 369 g

Molar mass of calcium hydroxide = 74.093 g/mole

Formula used :

$\text{Moles of calcium hydroxide}=\frac{\text{Mass of calcium hydroxide}}{\text{Molar mass of calcium hydroxide}}$

Now put all the given values in this formula, we get the moles of calcium hydroxide.

$\text{Moles of calcium hydroxide}=\frac{369g}{74.093g/mole}=4.98mole$

Therefore, the number of moles in 369 grams of calcium hydroxide is, 4.98 moles

7 0

2 years ago

The research step in the process of creating a hypothesis refers to _____.

Lelechka [254]

The is the B) doing background research about the question

3 0

2 years ago

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Which of the following is not a chemistry topic?

Tju [1.3M]

I’m pretty sure it’s D

6 0

2 years ago

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