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evablogger [386]
3 years ago
12

1.00 mL of a 250.0 µM solution of KCl is diluted to 50.0 mL. What is concentration of this solution?

Chemistry
1 answer:
Sever21 [200]3 years ago
3 0

Answer:

5.00 µM

Explanation:

Given data

  • Initial concentration (C₁): 250.0 µM
  • Initial volume (V₁): 1.00 mL
  • Final concentration (C₂): ?
  • Final volume (V₂): 50.0 mL

We can find the final concentration using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 250.0 µM × 1.00 mL / 50.0 mL

C₂ = 5.00 µM

The concentration of the diluted solution is 5.00 µM.

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Step 1. Start with the most complicated-looking formula (O₂?).

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We have fixed 2 O on the left. We need 2O on the right. Put a 2 in front of MgO.

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Every formula now has a coefficient. The equation should be balanced. Let’s check.

<u>Atom</u>  <u>On the left</u>  <u>On the righ</u>t

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All atoms are balanced.

The balanced equation is

2Mg + O₂ ⟶ 2MgO

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