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2 years ago

Helium gas diffuses 4 times as fast as an unknown gas. What is relative molecular mass of the gas

Chemistry

1 answer:

Inessa05 [86]2 years ago

7 0

The relative molecular mass of the gas : 64 g/mol

<h3>Further explanation</h3>

Given

Helium rate = 4x an unknown gas

Required

The relative molecular mass of the gas

Solution

Graham's Law

$\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }$

r₁=4 x r₂

r₁ = Helium rate

r₂ = unknown gas rate

M₁= relative molecular mass of Helium = 4 g/mol

M₂ = relative molecular mass of the gas

Input the value :

$\tt \dfrac{4r_2}{r_2}=\sqrt{\dfrac{M_2}{4} }\\\\16=\dfrac{M_2}{4}\\\\M_2=64~g/mol$

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(

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→

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⋅

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−−−−−−−−−−−−−

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I'll leave the answer rounded to two sig figs.

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Helium gas diffuses 4 times as fast as an unknown gas. What is relative molecular mass of the gas​

Helium gas diffuses 4 times as fast as an unknown gas. What is relative molecular mass of the gas