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Alexus [3.1K]
2 years ago
6

Helium gas diffuses 4 times as fast as an unknown gas. What is relative molecular mass of the gas​

Chemistry
1 answer:
Inessa05 [86]2 years ago
7 0

The relative molecular mass of the gas​ : 64 g/mol

<h3>Further explanation</h3>

Given

Helium rate = 4x an unknown gas

Required

The relative molecular mass of the gas​

Solution

Graham's Law

\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

r₁=4 x r₂

r₁ = Helium rate

r₂ = unknown gas rate

M₁= relative molecular mass of Helium = 4 g/mol

M₂ = relative molecular mass of the gas​

Input the value :

\tt \dfrac{4r_2}{r_2}=\sqrt{\dfrac{M_2}{4} }\\\\16=\dfrac{M_2}{4}\\\\M_2=64~g/mol

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Son las transformaciones que ocurren de un estado a otro de la materia, ocurren sin alterar la estructura molecular de la materi
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Los cambios de estado físico son transformaciones que ocurren de un estado de la materia a otro, sin cambiar la estructura molecular de la materia, es decir, sin transformarse en otras sustancias.

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Se puede decir que son diferentes solo por la organización de sus partículas, lo que determina su cambio de estado pero sin cambiar la estructura molecular.

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3 years ago
How many particles are in a 151 g sample of Li2O?
neonofarm [45]

Answer:

3.052 × 10^24 particles

Explanation:

To get the number of particles (nA) in a substance, we multiply the number of moles of the substance by Avogadro's number (6.02 × 10^23)

The mass of Li2O given in this question is as follows: 151grams.

To convert this mass value to moles, we use;

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number of particles (nA) of Li2O = 5.07 × 6.02 × 10^23

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