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Alexus [3.1K]
3 years ago
6

Helium gas diffuses 4 times as fast as an unknown gas. What is relative molecular mass of the gas​

Chemistry
1 answer:
Inessa05 [86]3 years ago
7 0

The relative molecular mass of the gas​ : 64 g/mol

<h3>Further explanation</h3>

Given

Helium rate = 4x an unknown gas

Required

The relative molecular mass of the gas​

Solution

Graham's Law

\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

r₁=4 x r₂

r₁ = Helium rate

r₂ = unknown gas rate

M₁= relative molecular mass of Helium = 4 g/mol

M₂ = relative molecular mass of the gas​

Input the value :

\tt \dfrac{4r_2}{r_2}=\sqrt{\dfrac{M_2}{4} }\\\\16=\dfrac{M_2}{4}\\\\M_2=64~g/mol

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How many moles of copper (Cu) are in 65.8 g Cu?
Veseljchak [2.6K]
<h2><u>Answer:</u></h2>

The correct answer is A) 1.04 mol Cu

{65.8 g     /   63.55 g/mol}

= 1.04 mol Cu

Explanation:

In  63.55  g  of copper metal there are  1 m o l  of  C u  atoms. By dividing the mass of Cu and molar mass, we can easily get the number of moles.


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3 years ago
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3 years ago
Given the Henry’s law constant for O2(4.34*109Pa) at 25° C, calculate the molar concentration of oxygen in air-saturated and O2s
Flauer [41]

This is an incomplete question, here is a complete question.

The Henry's law constant for oxygen dissolved in water is 4.34 × 10⁹ g/L.Pa at 25⁰C.If the partial pressure of oxygen in air is 0.2 atm, under atmospheric conditions, calculate the molar concentration of oxygen in air-saturated and oxygen saturated water.

Answer : The molar concentration of oxygen is, 2.67\times 10^2mol/L

Explanation :

As we know that,

C_{O_2}=k_H\times p_{O_2}

where,

C_{O_2} = molar solubility of O_2 = ?

p_{O_2} = partial pressure of O_2 = 0.2 atm  = 1.97×10⁻⁶ Pa

k_H = Henry's law constant  = 4.34 × 10⁹ g/L.Pa

Now put all the given values in the above formula, we get:

C_{O_2}=(4.34\times 10^9g/L.Pa)\times (1.97\times 10^{-6}Pa)

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Now we have to molar concentration of oxygen.

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Therefore, the molar concentration of oxygen is, 2.67\times 10^2mol/L

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3 years ago
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lina2011 [118]
Yes, hope this helped!
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Scilla [17]

Answer:

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