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SVETLANKA909090 [29]
3 years ago
14

A mixture of gaseous reactants is put into a cylinder, where a chemical reaction turns them into gaseous products. The cylinder

has a piston that moves in or out, as necessary, to keep a constant pressure on the mixture of . The cylinder is also submerged in a large insulated water bath. This chemical reaction is known to release of energy. The temperature of the water bath is monitored, and it is determined from this data that of heat flows out of the system during the reaction.
a. Does the temperature of the water bath go up or down?
b. Does the piston move in or out?
c. Does heat flow into or out of the gaseous mixture?
d. How much heat flows?
Chemistry
1 answer:
IRISSAK [1]3 years ago
7 0

Answer:

A. Up

B. Out

C. Out

D. To equilibrum

Explanation:

a. The reaction in an exothermic reaction so this means heat is given off. If the cylinder is thin enough heat will transfer to the water bath

b. Since the products will create heat which will increase pressure, the piston in an attempt to maintaining a constant pressure will move up to accommodate building pressure.

c. Heat will flow out of the gaseous mixture as this reaction creates heat as a product as well

d. Heat will flow out in the capacity to create an equilibrium with the water bath that it is in.

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A sample of nitrogen gas occupies 1.55 L at
34kurt

Answer:

The new volume after the temperature reduced to -100 °C is 0.894 L

Explanation:

Step 1: Data given

Volume of nitrogen gas = 1.55 L

Temperature = 27.0 °C = 300 K

The temperature reduces to -100 °C = 173 K

The pressure stays constant

Step 2: Calculate the new volume

V1/T1 = V2/T2

⇒with V1 = the initial volume of the gas = 1.55 L

⇒with T1 = the initial temperature = 300 K

⇒with V2 = the new volume = TO BE DETERMINED

⇒with T2 = the reduced temperature = 173 K

1.55 L / 300 K = V2 / 173 K

V2 = (1.55L /300K) * 173 K

V2 = 0.894 L

The new volume after the temperature reduced to -100 °C is 0.894 L

3 0
3 years ago
A woman’s menstrual cycle usually lasts about 28 days T/F
Sergio039 [100]

A woman’s menstrual cycle usually lasts about 28 days *TRUE*

6 0
3 years ago
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Which method preserves an image of a leaf?.
Sav [38]

Answer:

Tree sap flows over the leaf and preserves it.

Explanation:

Amber would preserve the image.

5 0
3 years ago
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Yeast converts glucose to ethanol and carbon dioxide during a process known as anaerobic fermentation. The chemical reaction is
Korolek [52]

Answer:

102g

Explanation:

To find the mass of ethanol formed, we first need to ensure that we have a balanced chemical equation. A balanced chemical equation is where the number of atoms of each element is the same on both sides of the equation (reactants and products). This is useful as only when a chemical equation is balanced, we can understand the relationship of the amount (moles) of reactant and products, or to put it simply, their relationship with one another.

In this case, the given equation is already balanced.

\tex{C_6H_{12}O_6} \longrightarrow 2 \ C_2H_6O + 2 \ CO_2

From the equation, the amount of ethanol produced is twice the amount of yeast present, or the same amount of carbon dioxide produced. Do note that amount refers to the number of moles here.

Mole= Mass ÷Mr

Mass= Mole ×Mr

<u>Method 1: using the </u><u>mass of glucose</u>

Mr of glucose

= 6(12) +12(1) +6(16)

= 180

Moles of glucose reacted

= 200 ÷180

= \frac{10}{9} mol

Amount of ethanol formed: moles of glucose reacted= 2: 1

Amount of ethanol

= 2(\frac{10}{9} )

= \frac{20}{9} mol

Mass of ethanol

= \frac{20}{9} \times[2(12)+6+16]

= \frac{20}{9}(46)

= 102 g (3 s.f.)

<u>Method 2: using </u><u>mass of carbon dioxide</u><u> produced</u>

Mole of carbon dioxide produced

= 97.7 ÷[12 +2(16)]

= 97.7 ÷44

= \frac{977}{440} mol

Moles of ethanol: moles of carbon dioxide= 1: 1

Moles of ethanol formed= \frac{977}{440} mol

Mass of ethanol formed

= \frac{977}{440} \times[2(12)+6+16]

= 102 g (3 s.f.)

Thus, 102 g of ethanol are formed.

Additional:

For a similar question on mass and mole ratio, do check out the following!

  • brainly.com/question/1685725
8 0
2 years ago
A 50 L cylinder is filled with argon gas to a pressure of 10130.0 kPa at 300°C. How many moles of argon gas does the cylinder co
KengaRu [80]
In this problem, we need to use the ideal gas law. The following is the formula used in ideal gas law: PV = nRT, where n refers to the moles and R is the gas constant.

Given 
P = 10130.0 kPa 
V = 50 L
T = 300 degree celcius + 273.15 = 573.15 K
R = 8.314 L. kPa/K.mol

Solution
To get the moles which represent the "n" in the formula, we need to rearrange the equation.

PV = nRT                      PV
----    ------    --->    n = --------
 RT     RT                       RT

          10130.0 kPa  x 50 L
n= ---------------------------------------------
       8.314 L. kPa/K.mol  x 573.15 K
             506,500 
  =  ----------------------------
         4,765.17  mol K

=106.29 mol Ar

So the moles of argon gas is 106.29 moles 
8 0
3 years ago
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