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stealth61 [152]
3 years ago
13

what is the geocentric model of stars and planets? a.) the belief that stars and planets revolve around the earth b.) the belief

that planets revolve around the stars c.) the belief that planets and the moon revolve around earth d.) the belief that stars and planets revolve around the sun
Physics
1 answer:
amid [387]3 years ago
7 0

a.) the belief that stars and planets revolve around the earth

Explanation:

The geocentric model of stars and planets is the belief that stars and planets revolves around the earth.

The model places the earth at the center of the system.

  • Geo - earth ; centric - center
  • This was the original school of thought about the way the earth relates to other bodies in the universe.
  • This model was replaced by the heliocentric universe in which stars are at the center and the planets revolves round them.
  • The idea was put forward by Nicola Copernicus

learn more:

Energy of the sun brainly.com/question/1140127

#learnwithBrainly

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Suppose a radar gun sends out radio waves with a frequency of 2,000,000.0 Hz. The waves bounce off a moving car and return with
Igoryamba

Answer:

300,000,030m/s

Explanation:

Using the relationship between frequency and speed of a wave;

F ∝ V

F = kV

k = F/V

F1/V1 = F2/V2 = k

Let F1 be the frequency of the radio wave = 2,000,000.0Hz

V1 be the speed of light = 300,000,000m/s

F2 = frequency produced by the car = 2,000,000.2Hz

V2 be the velocity of the moving car

Substituting this values in the equation above;

2,000,000/300,000,000 = 2,000,000.2/V2

Cross multiplying

2,000,000V2 = 300,000,000×2,000,000.2

2V2 = 300×2,000,000.2

V2 = 150×2,000,000.2

V2 = 300,000,030m/s

The velocity of the car is 300,000,030m/s

6 0
3 years ago
If you are driving 72 km/h along a straight road and you look to the side for 4.0 s, how far do you travel during this inattenti
Ann [662]
We know that speed equals distance between time. Therefore to find the distance we have that d = V * t. Substituting the values d = (72 Km / h) * (1h / 3600s) * (4.0 s) = 0.08Km.Therefore during this inattentive period traveled a distance of 0.08Km
8 0
3 years ago
On a touchdown attempt, 95.00 kg running back runs toward the end zone at 3.750 m/s. A 113.0 kg line-backer moving at 5.380 m/s
dsp73

Answer:

(a) 1.21 m/s

(b) 2303.33 J, 152.27 J

Explanation:

m1 = 95 kg, u1 = - 3.750 m/s, m2 = 113 kg, u2 = 5.38 m/s

(a) Let their velocity after striking is v.

By use of conservation of momentum

Momentum before collision = momentum after collision

m1 x u1 + m2 x u2 = (m1 + m2) x v

- 95 x 3.75 + 113 x 5.38 = (95 + 113) x v

v = ( - 356.25 + 607.94) / 208 = 1.21 m /s

(b) Kinetic energy before collision = 1/2 m1 x u1^2 + 1/2 m2 x u2^2

                                               = 0.5 ( 95 x 3.750 x 3.750 + 113 x 5.38 x 5.38)

                                               = 0.5 (1335.94 + 3270.7) = 2303.33 J

Kinetic energy after collision = 1/2 (m1 + m2) v^2                

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3 years ago
Which of the following statements correctly describes the position of the intake and exhaust valves during most of the power sta
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Both valves are closed during the power stroke.

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If either of the valves was open, even just a crack,
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pushing the piston.

5 0
3 years ago
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Which of the following particles are responsible for producing electrical<br> energy?
kherson [118]
The answer is Electrons
4 0
3 years ago
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