Ask question

Ask question

All categories

stealth61 [152]

3 years ago

13

what is the geocentric model of stars and planets? a.) the belief that stars and planets revolve around the earth b.) the belief

that planets revolve around the stars c.) the belief that planets and the moon revolve around earth d.) the belief that stars and planets revolve around the sun

1 answer:

amid [387]3 years ago

7 0

a.) the belief that stars and planets revolve around the earth

Explanation:

The geocentric model of stars and planets is the belief that stars and planets revolves around the earth.

The model places the earth at the center of the system.

Geo - earth ; centric - center
This was the original school of thought about the way the earth relates to other bodies in the universe.
This model was replaced by the heliocentric universe in which stars are at the center and the planets revolves round them.
The idea was put forward by Nicola Copernicus

learn more:

Energy of the sun brainly.com/question/1140127

#learnwithBrainly

You might be interested in

If you begin with 40 grams of a radioactive isotope and end with 10 grams, how many half-lifes of the radioactive isotope have p

Rom4ik [11]

30 grams of radioactive isotope have passed.

8 0

2 years ago

In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 71.0 m/s. Th

elena55 [62]

<u>Answer:</u>

<em>Thunderbird is 995.157 meters behind the Mercedes</em>

<u>Explanation:</u>

It is given that all the cars were moving at a speed of 71 m/s when the driver of Thunderbird decided to take a pit stop and slows down for 250 m. She spent 5 seconds in the pit stop.

Here final velocity $v=0 \ m/s$

initial velocity $u= 71 m/s$ distance

Distance covered in the slowing down phase = $250 m$

$v^2-u^2=2as$

$a= \frac {(v^2-u^2)}{2s}$

$a = \frac {(0^2-71^2)}{(2 \times 250)}=-10.082 \ m/s^2$

$v=u+at$

$t= \frac {(v-u)}{a}$

$= \frac {(0-71)}{(-10.082)}=7.042 s$

$t_1=7.042 s$

The car is in the pit stop for 5s $t_2=5 s$

After restart it accelerates for 350 m to reach the earlier velocity 71 m/s

$a= \frac {(v^2-u^2)}{(2\times s)} = \frac{(71^2-0^2)}{(2 \times 370)} =6.81 \ m/s^2$

$v=u+at$

$t= \frac{(v-u)}{a}$

$t= \frac{(71-0)}{6.81}= 10.425 s$

$t_3=10.425 s$

total time= $t_1 +t_2+t_3=7.042+5+10.425=22.467 s$

Distance covered by the Mercedes Benz during this time is given by $s=vt=71 \times 22.467= 1595.157 m$

Distance covered by the Thunderbird during this time= $250+350=600 m$

Difference between distance covered by the Mercedes and Thunderbird

= $1595.157-600=995.157 m$

Thus the Mercedes is 995.157 m ahead of the Thunderbird.

6 0

2 years ago

You can burn fat by all of the following Question 2 options:

Katen [24]

Answer:

D

Explanation:

6 0

2 years ago

Read 2 more answers

A fish cannot be killed by throwing an arrow into the water why?

olga55 [171]

Answer:

a fish cannot be killed by throwing an arrow into the water because you have to throw the arrow at the fish not just in the water….

Explanation:

common sense TwT

duhhh

3 0

1 year ago

Read 2 more answers

If a machine has an efficiency of 40%, and you do 1,000 J of work on the machine, what will be the work output of the machine?

Nata [24]

Answer:

400 J

Explanation:

The efficiency of a machine is defined as

$\eta = \frac{W_{out}}{W_{in}}$

where

$W_{out}$ is the work output

$W_{in}$ is the work input

For this machine, we know the following

$W_{in} = 1000 J$ is the work in input

$\eta = 40\% = 0.40$ is the efficiency

Solving for the work output, we find

$W_{out} = \eta W_{in} = (0.40)(1000)=400 J$

5 0

3 years ago