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uysha [10]
3 years ago
8

Question 5 (1 point)

Physics
1 answer:
katovenus [111]3 years ago
8 0

Answer:

The horizontal distance the ball travels is approximately 4.055 meters

Explanation:

The given parameters are;

The height from which the child kicks the ball = 3.5 m

The horizontal speed of the ball = 4.8 m/s

Therefore, we have;

The time it takes the ball to hit the ground is given by the relation;

h = u·t + 1/2·g·t²

Where;

u = The initial vertical velocity of the ball = 0 m/s

t = The time it takes the ball to hit the ground

g = The acceleration due to gravity = 9.81 m/s²

h = The height of the ball = 3.5 m

3.5 = 0 × t + 1/2 × 9.81 × t²

3.5 = 1/2 × 9.81 × t²

∴ t² = 3.5/(1/2 × 9.81)

∴ t = √(3.5/(1/2 × 9.81) = 0.8447 s

t ≈ 0.8447 s

The time the ball takes in flight = t ≈ 0.8447 s

Therefore;

The horizontal distance the ball travels = The horizontal velocity × The time of flight

∴ The horizontal distance the ball travels = 4.8 × 0.8447 ≈ 4.055

The horizontal distance the ball travels ≈ 4.055 meters.

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Describe in terms of kinetic and potential energy what happens if an apple falls from a tree and comes to rest on the ground( wr
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As the apple falls the height or the distance reduces and PE becomes reduces. But it gains Kinetic energy due to its speed.

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Answer:

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where 13.606 eV   is the ground state energy and n is an integer

an atom transition is the jump of an electron from an initial state to a final state of lesser emergy

            ΔE = 13.606 (1 / n_{f}^{2} - 1 / n_{i}^{2})

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            DE = 12.094 eV

let's reduce the energy to the SI system

            DE = 12.094 eV (1.6 10⁻¹⁹ J / 1 ev) = 10.35 10⁻¹⁹ J

let's find the wavelength is this energy, let's use Planck's equation to find the frequency

            E = h f

             f = E / h

            f = 19.35 10⁻¹⁹ / 6.63 10⁻³⁴

            f = 2.9186 10¹⁵ Hz

now we can look up the wavelength

           c = λ f

           λ = c / f

           λ = 3 10⁸ / 2.9186 10¹⁵

           λ = 1.0278  10⁻⁷ m

let's reduce to nm

            λ = 102.78  nm

This radiation is in the UV range, which occurs for wavelengths less than 400 nm.

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