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3 years ago

12

Explain Hardy-Weinberg equilibrium and why it is so important, especially since all of its assumptions seem so unrealistic and d

ifficult to meet.

1 answer:

Pachacha [2.7K]3 years ago

7 0

Answer:

The Hardy-Weinberg equilibrium principle states that ideally a population's genetic variation does not change for every generation. That is with random mating within a large population where all influencing factors are constant, it predicts the constant frequencies of genotype and allele because of their equilibrium state

Explanation:

The principle provides a foundation for studying popupulation variation between generations when influencing factors such as genetic mutations, natural selection forces, guided mating, drift in genetics and transfer of genetic variation between populations are considered

You might be interested in

Complete the sentence to identify concepts of the special theory of relativity.

Rudiy27

Answer: time; mass

Explanation:

The equation E=mc^2 shows that energy, e, and mass, m, are linked.

For objects moving in a straight line, the special theory of relativity applies to show that space and time are linked.

7 0

3 years ago

8) T F A car is being towed at constant velocity on a horizontal road using a horizontal chain. The tension in the chain must be

Stels [109]

Answer:

False

Explanation:

The tension in the chain must be equal to the frictional force acting on the car, not to its weight.

In fact, we have 4 forces acting on the car

- Its weight: downward

- The normal reaction of the road on the car: upward --> this force balances the weight, so the net force along the vertical direction is zero

- The tension in the chain: forward

- The frictional force between the road's surface and the tires of the car: backward

We can consider the horizontal motion only: we are said that the car is moving at constant velocity, so the horizontal acceleration is zero. According to Newton's second law:

$\sum F = ma$

zero acceleration means that the resultant of the forces on the car is zero. But there are only 2 forces acting on the car in the horizontal direction: the tension in the chain (forward) and the frictional force (backward). Since their resultant must be zero, it means that the two forces must be equal and opposite: therefore, the tension in the chain must be equal to the frictional force.

8 0

3 years ago

The waves with the lowest energy and lowest frequencies of the electromagnetic spectrum are the

Andru [333]

<span>The waves with the lowest energy and lowest frequencies of the electromagnetic spectrum are the "Radio waves"

So, option B is your answer

Hope this helps!
</span>

5 0

4 years ago

What is the net Force needed to get a 16 kg box moving 4 m/s^2?

igomit [66]

Answer:

The net force should be of a magnitude of 64 N

Explanation:

We use Newton's second Law for this:

$F_{net} = m\,*\,a$

which for our case gives:

$F_{net} = m\,*\,a=16\,(4)\,N= 64\,\,N$

3 0

3 years ago

A car is parked on a cliff overlooking the ocean on an incline that makes an angle of 24.0° below the horizontal. The negligent

anzhelika [568]

Answer:

The position is $P = 47.4 \ m$ relative to the base of the ocean

Explanation:

From the question we are told that

The angle made by the incline with the horizontal is $\theta = 24.0 ^o$

The constant acceleration is $a = 3.82 \ m/s^2$

The distance covered is $d = 60.0 \ m$

The height of the cliff is $h = 50 .0 \ m$

The velocity of the car is mathematically represented as

$v^2 = u^2 + 2ad$

The initial velocity of the car is u= 0

So

$v^2 = 2ad$

substituting values

$v^2 = 2 * 3.82 * 60$

$v = 21.4 \ m/s$

The vertical component of this velocity is

$v_v = -v * sin(\theta )$

substituting values

$v_v = -21.4 * sin(24.0)$

$v_v = -8.7 \ m/s$

The negative sign is because is moving in the negative direction of the y-axis

The horizontal component of this velocity is

$v_h = v * cos (\theta)$

$v_h = 21.4 * cos (24.0)$

$v_h = 19.5 \ m/s$

Now according to equation of motion we have

$h = v_v*t - \frac{1}{2} * g t^2$

substituting values

$50 = -8.7 t - \frac{1}{2} * 9.8 t^2$

$4.9t^2 +8.7t -50 = 0$

using quadratic equation we have that

$t_1 = 2.42\ s \ and\ t_2 = -4.20\ s$

given that time cannot be negative

$t = 2.42 \ s$

The car’s position relative to the base of the cliff when the car lands in the ocean is mathematically evaluate as

$P = v_h * t$

substituting values

$P = 19.5 * 2.43$

$P = 47.4 \ m$

5 0

3 years ago