8) T F A car is being towed at constant velocity on a horizontal road using a horizontal chain. The tension in the chain must be
1 answer:
Answer:
False
Explanation:
The tension in the chain must be equal to the frictional force acting on the car, not to its weight.
In fact, we have 4 forces acting on the car
- Its weight: downward
- The normal reaction of the road on the car: upward --> this force balances the weight, so the net force along the vertical direction is zero
- The tension in the chain: forward
- The frictional force between the road's surface and the tires of the car: backward
We can consider the horizontal motion only: we are said that the car is moving at constant velocity, so the horizontal acceleration is zero. According to Newton's second law:
zero acceleration means that the resultant of the forces on the car is zero. But there are only 2 forces acting on the car in the horizontal direction: the tension in the chain (forward) and the frictional force (backward). Since their resultant must be zero, it means that the two forces must be equal and opposite: therefore, the tension in the chain must be equal to the frictional force.
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Answer:
(a) θ= 43.89°
(b)
Explanation:
Ball 1:
Ball 2:
As the collision is elastic, it means that kinetic energy and momentum are conserved. Following that, we apply the law of conservation of energy and momentum:
and
Where u is the velocity before the collision, and v are the velocities after the collision. Both previous equations can be simplified as:
and
This because the two balls have the same mass. We know that the cue ball is deflected and makes an angle of 30°. From conservation in x-direction, we get::
and
Solving we get:
From conservation in y-direction, we get:
From this, we solve this equation system and get the answers. Remember to add 30° to the angle obtained.