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3 years ago

15

Jake's baby pool is empty. His mom fills it with a garden hose at a rate of 2 gallons per minute. What is the initial value for

the scenario described? (4 points) 0 1 2 60

2 answers:

VMariaS [17]3 years ago

5 0

Answer:

O is the answer.

Step-by-step explanation: The initial value starts at 0 because the pool is empty.

Phoenix [80]3 years ago

3 0

0 is the correct answer. It is initially 0 as it is empy. <span />

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Which expression is equivalent to (21/2 x 2 3/4)^2

sasho [114]

ANSWER

$(2 \frac{1}{2} \times 2 \frac{3}{4} ) ^{2} = 47 \frac{17}{64}$

EXPLANATION

To find the expression that is equivalent to
$(2 \frac{1}{2} \times 2 \frac{3}{4} ) ^{2}$

we need to simplify it.

We convert the mixed numbers to improper fraction as follows.

$(2 \frac{1}{2} \times 2 \frac{3}{4} ) ^{2} = ( \frac{2 \times 2 + 1}{2} \times \frac{2 \times 4 + 3}{4} ) ^{2}$

This will give us,

$(2 \frac{1}{2} \times 2 \frac{3}{4} ) ^{2} = ( \frac{4 + 1}{2} \times \frac{8 + 3}{4} )^{2}$

$(2 \frac{1}{2} \times 2 \frac{3}{4} ) ^{2} = ( \frac{5}{2} \times \frac{11}{4} )^{2}$

We multiply the expression in the parenthesis on the right hand side to obtain,

$(2 \frac{1}{2} \times 2 \frac{3}{4} ) ^{2} = ( \frac{55}{8} )^{2}$

We share the exponent for the numerator and the denominator separately.

$(2 \frac{1}{2} \times 2 \frac{3}{4} ) ^{2} = \frac{ {55}^{2} }{ {8}^{2} }$

This simplifies to,

$(2 \frac{1}{2} \times 2 \frac{3}{4} ) ^{2} = \frac{ {3025} }{ {64}}$

We write the final answer as a mixed number to obtain,

$(2 \frac{1}{2} \times 2 \frac{3}{4} ) ^{2} = 47 \frac{17}{64}$

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