Answer:
Atoms He (Avogadro’s number) → Moles of He (molar mass of He) → Mass of He
• molar mass of He (from the periodic table) = 4.003 g/mol
• Avogadro’s Number: Avogadro’s number gives us the number of entities present in 1 mole: 6.022 × 1023 He atoms in 1 mole of He
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Answer:
Explanation:
Given that:-
Mass of the hydrated salt = 7.028 g
Mass of the anhydrous salt = 3.100 g
Mass of water eliminated = Mass of the hydrated salt - Mass of the anhydrous salt = 7.028 - 3.100 g = 3.928 g
<u>Moles of water: </u>
Mass of water = 3.928 g
Molar mass of = 18 g/mol
The formula for the calculation of moles is shown below:
Thus, moles are:
<u>Moles of anhydrous salt: </u>
Amount = 3.100 g
Molar mass of = 142.04 g/mol
Thus, moles are:
The simplest ratio of the two are:
=0.02182 : 0.2212 = 1 : 10
<u>Hence, the formula for hydrate is:- </u>
Answer:
the first line
Explanation:
A rarefaction is a region in a longitudinal wave where the particles are furthest apart. ... The region where the medium is compressed is known as a compression and the region where the medium is spread out is known as a rarefaction.
use this picture as a reference:
