How many grams of propanol (C3H7OH, 60.10 g/mol) would be needed to make 750 mL of a solution with an osmotic pressure of 25 atm

Question

Alex17521 [72]

3 years ago

14

How many grams of propanol (C3H7OH, 60.10 g/mol) would be needed to make 750 mL of a solution with an osmotic pressure of 25 atm

at 25°C? (R = 0.0821 L.atm/K.mol)

Chemistry

1 answer:

Ierofanga [76] · Answer 1 · 2022-08-14T00:52:45+03:00

Ierofanga [76]3 years ago

3 0

Answer:

= 46.06 grams

Explanation:

P=cRT

25 = c (0.0821)(298)

concentration = c = 1.021 M

number of moles = (1.021)(0.75) = 0.7664 moles

mass = (0.7664)(60.10)=40.06 grams