All categories

3 years ago

What is the relationship between the ratios?

Mathematics

1 answer:

Lesechka [4]3 years ago

5 0

Answer:

NOT PROPORTIONAL

Step-by-step explanation:

The given two fractions are: $\frac{5}{8}$ and $\frac{8}{10}$ .

Proportional fractions are those which have the same value when to reduced to the simplest form.

Consider two fractions $\frac{p}{q}$ and $\frac{x}{y}$ .

We say they are proportional if $p : q = x : y$ .

Or, if $py = qx$ then we can say the fractions are proportional.

Here the fractions are: $\frac{5}{8}$ and $\frac{8}{10}$ .

LHS: 5 X 10 = 50.

RHS: 8 X 8 = 64.

Clearly they are not equal. So, we can say these two fractions are not proportional.

You might be interested in

PLS HELP ILL MARK CROWN

jok3333 [9.3K]

Answer:

4x−7

Step-by-step explanation:

Being given our polynomial:

$4x^{2}$ + x - 14,

We must find the roots to get our answer.

x = (- 1 ± √(1 - 4*4*(-14)) / 8

x = (- 1 ± √225) / 8

x = ( -1 ± 15) / 8

x₁ = (- 1 + 15)/ 8 = 14/8 = 7 / 4

x₂ = (- 1 - 15) / 8 = - 16/2 = - 8

The factors we came up with:

(x - x₁)(x - x₂)

(x - 7/4)(x + 8)

1/4(4x - 7)(x + 8)

So,

The correct option is C.

6 0

3 years ago

Read 2 more answers

Javier is considering two lawn care services. Premier Landscaping charges $15.00 for travel to the job site and $55.00 per hour

Wittaler [7]

Answer:

Time in which both companies charge same cost = 1.5 hour

Step-by-step explanation:

Given:

Fixed Variable

Premier Landscaping charges $15 $55

Ace Landscaping charges $65

Find:

Time in which both companies charge same cost:

Computation:

Assume in X time both companies charge same cost:

So,

Premier Landscaping total cost = Ace Landscaping total cost

⇒ $15 + $55(Time taken) = $65 (Time taken)

⇒ $15 = $65 (Time taken) - $55(Time taken)

⇒ $15 = $10 (Time taken)

⇒ Time taken = 1.5 hour

Time in which both companies charge same cost = 1.5 hour

6 0

3 years ago

Suppose that S is the set of successful students in a classroom, and that F stands for the set of freshmen students in that clas

lora16 [44]

Answer:

b) 24

Step-by-step explanation:

We solve building the Venn's diagram of these sets.

We have that n(S) is the number of succesful students in a classroom.

n(F) is the number of freshmen student in that classroom.

We have that:

$n(S) = n(s) + n(S \cap F)$

In which n(s) are those who are succeful but not freshmen and $n(S \cap F)$ are those who are succesful and freshmen.

By the same logic, we also have that:

$n(F) = n(f) + n(S \cap F)$

The union is:

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

In which

$n(S \cup F) = 58$

$n(s) = n(S) - n(S \cap F) = 54 - n(S \cap F)$

$n(f) = n(F) - n(S \cap F) = 28 - n(S \cap F)$

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

$58 = 54 - n(S \cap F) + 28 - n(S \cap F) + n(S \cap F)$

$n(S \cap F) = 24$

So the correct answer is:

b) 24

3 0

3 years ago

On Friday ,537 people attended a play.for Saturdays matinee there were 812 people.about how many more people attended the play o

Ronch [10]

812-537=275; 275 more people attended the play on Saturday than on Friday.

8 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B400%20%5Ctimes%20400%20-%2024%20%5Ctimes%20400%20-%20360%20%5Ctimes%20400%20-%202

max2010maxim [7]

Answer:

$\sqrt{400 \times 400 - 24 \times 400 - 360 \times 400 - 200} \\ \\ = \sqrt{160000 - 9600 - 144000 - 200} \\ \\ = \sqrt{160000 - 9600 - 144000 - 200} \\ \\ = \sqrt{160000 - 153,800} \\ \\ = \sqrt{6200} \\ \\ = 78.74 \\ \\$

7 0

3 years ago