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rodikova [14]
3 years ago
9

You live 6 kilometers from your school. How many meters do you live from school?

Chemistry
2 answers:
Phantasy [73]3 years ago
7 0
1000 m = 1 km
so if you have 6 km you have 1000×6= 6000m
So you live 6000m from school
Snezhnost [94]3 years ago
5 0
Answer:  6,000 m .  (or, write as:  6,000 meters).
_______________________________________________________
Explanation:
_________________________________________________
Note the exact conversion:  1 km = 1000 m .
______________________________________________________
Note:  "km" is an abbreviated form of "kilometer(s)".
              "m" is an abbreviated form of "meter(s)".
______________________________________________________
Here is one way to solve, using a method called "dimensional analysis":
_______________________________________________________
  Given:  6 km ;  convert to  "m"  ; 
______________________________________________________
         →  6 km =  <span>   ?  </span>  m  ;
___________________________________________________
        →  6 km * \frac{1000  m}{1 km}  =   ?    m ;
___________________________________________________
        →  On the "left-hand side" of the equation, the units of  "km"                                  "cancel out" to "1" ;  and we are left with:
_______________________________________________
        →  6  * \frac{1000 m}{1   =    ?  m ;
_______________________________________________
       .→  6  * 1000 m   =  <span> <span>   ?</span></span>   m  ;
_______________________________________________
                            →   =  6,000 m ; or write as:  6,000 meters .
___________________________________________________
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Answer:

Pb(NO₂)₂(aq) + 2 LiCl(aq) ⇒ PbCl₂(s) + 2 LiNO₂(aq)

Explanation:

Let's consider the reaction between aqueous lead (II) nitrite and aqueous lithium chloride to form solid lead (II) chloride and aqueous lithium nitrite.

Pb(NO₂)₂(aq) + LiCl(aq) ⇒ PbCl₂(s) + LiNO₂(aq)

This is a double displacement reaction. We will start balancing Cl by multiplying LiCl by 2.

Pb(NO₂)₂(aq) + 2 LiCl(aq) ⇒ PbCl₂(s) + LiNO₂(aq)

Now, we have to balance Li by multiplying LiNO₂ by 2.

Pb(NO₂)₂(aq) + 2 LiCl(aq) ⇒ PbCl₂(s) + 2 LiNO₂(aq)

The equation is now balanced.

4 0
3 years ago
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6 0
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A nuclear waste site. cesium-137 is a particularly dangerous by-product of nuclear reactors. it has a half-life of 30 years. it
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The mass decay rate is of the form
m(t) = m_{0} e^{-kt}
where
m₀ = 3000 g,the initial mass
k = the decay constant
t = time, years.

Because the half-life is 30 years, therefore
e^{-30k} =  \frac{1}{2} \\\ -30k = ln(0.5) \\ k =  \frac{ln(0.5)}{-30} =0.0231

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3 years ago
How many grams of NaCl are in 3.5 mol of NaCl? Also, how many moles of NaCl are in 150 g of NaCl?​
alexandr402 [8]

Answer:

204.5505 grams

2.5666 moles

Explanation:

For the first question, multiply 3.5 (# of moles) by 58.443 (g/mol for NaCl).

58.443 * 3.5

<em>I'll distribute 3.5 into 58.443.</em>

(3.5 * 50) + (3.5 * 8) + (3.5 * 0.4) + (3.5 * 0.04) + (3.5 * 0.003)

175 + 28 + 1.4 + 0.14 + 0.0105

203 + 1.4 + 0.14 + 0.0105

204.4 + 0.14 + 0.0105

204.54 + 0.0105

204.5505 grams

There are 204.5505 grams in 3.5 moles of NaCl.

For the second question, divide 150 (# of grams) by 58.443 (g/mol for NaCl). I'll convert both into fractions.

150/1 * 1000/58443

150000/58443

2.56660336 moles

2.5666 moles (rounded to 4 places to keep consistency with the first answer) are in 150 grams of NaCl.

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Answer: 0.79

Explanation:

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