The rate of a reaction can be increased by:
-using a catalyst- it lowers the activation energy and leads to less energy required to break bonds of reactants. This lower activation energy leads to more products formed with less time, hence an increase reaction rate.
-increasing temperature- the particles of a molecule move faster and undergo more collision which leads to an increase in the speed of the reaction.
-increasing pressure- means there is more particles of reactants in a reduced volume. The particles do not need to move long distances to find another particle to react with, hence the rate of reaction increases.
Using an inhibitor will not increase the rate of the reaction because, an inhibitor binds to the active site where a catalyst is supposed to act. This means a higher activation energy and thus a decrease in reaction rate.
Likewise, decreasing the concentration implies few particles available to collide with each other and that slow down the speed of the reaction.
Answer: Bond Polarity | Chemistry for Non-Majors - Lumen Learning
Explanation:
We calculate it as follows:
Moles CO2 = 0.01849 g / 44 = 0.000420
<span>Mass C = 0.000420 x 12 = 0.00504 g </span>
<span>Moles H = 2 x 0.006232 / 18 = 0.000692 </span>
<span>Mass H = 0.000692 g </span>
<span>Mass O = 0.005982 - ( 0.00504 + 0.000692) = 0.00025 </span>
<span>Moles O = 0.00025 / 16 = 0.0000156 </span>
<span>C 0.000420
H 0.000692
O 0.0000156
</span>
<span>divide each by the smallest value, giving you the chemical formula as:
</span><span>
C27H44O</span>
Answer:
The error would be $13.
Explanation:
Given data:
Actual payment = $325
estimated payment = $312
Error = ?
Solution:
Error = Estimated payment - Actual payment
Error = $312 - $325
Error = -$13
we can discard the negative sign and consider the absolute value. The error would be $13.
Answer:

Explanation:
B.

BALANCED. 7C, 16H, and 22O on each side of equation.
A.

NOT BALANCED. 7C on left and 6C on right.
C.

NOT BALANCED. 16H on left and 10H on right.
D.

NOT BALANCED. 7C on left and 14C on right.