Answer:
Dalton's law is fulfilled, since the elements in each compound of the example are related to each other in different proportions forming two different compounds; so for case a) and b) you have 15.54% and 9.323% P respectively for each compounds, that are equivalent to 0.2912 g P for every g Cl and the other produced 0,1747 g P for every g Cl.
Explanation:
Dalton's Law ( law of multiple proportions):
When two or more elements combine to give more than one compound, a variable mass of one of them joins a fixed mass of the other, and the first is related to canonical and indistinct numbers.
a) for the compounds A:
⇒ 0.2912 g P / gCl * ( 35.45 g CL / mol CL) * ( mol Cl / mol PCl ) * ( mol PCl / 66.427 g PCl ) = 0.1554 g P / g PCl
⇒ % P = 0.1554 * 100 = 15.54 %
b) for the compunds B:
⇒ 0.1747 g P / g Cl * ( 35.45 g Cl / mol Cl ) * ( mol Cl / mol PCl ) * ( mol PCl / 66.427 g PCl ) = 0.09323 g P / g PCl
⇒ % P = 9.323 %
I want to talk to you girl?
Answer:
Part A
![Rate = -\frac{1}{2}\frac{\Delta A}{\Delta t} =-\frac{\Delta B}{\Delta t} = \frac{1}{3}\frac{\Delta C}{\Delta t}](https://tex.z-dn.net/?f=Rate%20%3D%20-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7B%5CDelta%20A%7D%7B%5CDelta%20t%7D%20%3D-%5Cfrac%7B%5CDelta%20B%7D%7B%5CDelta%20t%7D%20%3D%20%5Cfrac%7B1%7D%7B3%7D%5Cfrac%7B%5CDelta%20C%7D%7B%5CDelta%20t%7D)
Part B
Part C
![\frac{\Delta C}{\Delta t} = 0.15 M s^{-1}](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20C%7D%7B%5CDelta%20t%7D%20%3D%200.15%20M%20s%5E%7B-1%7D)
Explanation:
For a general reaction,
![aA(g) + bB(g) \rightarrow cC(g)](https://tex.z-dn.net/?f=aA%28g%29%20%2B%20bB%28g%29%20%5Crightarrow%20cC%28g%29)
Rate is given by:
Rate: ![Rate = -\frac{1}{a}\frac{\Delta A}{\Delta t} =-\frac{1}{b}\frac{\Delta B}{\Delta t} = \frac{1}{c}\frac{\Delta C}{\Delta t}](https://tex.z-dn.net/?f=Rate%20%3D%20-%5Cfrac%7B1%7D%7Ba%7D%5Cfrac%7B%5CDelta%20A%7D%7B%5CDelta%20t%7D%20%3D-%5Cfrac%7B1%7D%7Bb%7D%5Cfrac%7B%5CDelta%20B%7D%7B%5CDelta%20t%7D%20%3D%20%5Cfrac%7B1%7D%7Bc%7D%5Cfrac%7B%5CDelta%20C%7D%7B%5CDelta%20t%7D)
So, for the given reaction:
![2A(g) + B(g) \rightarrow 2C(g)](https://tex.z-dn.net/?f=2A%28g%29%20%2B%20B%28g%29%20%5Crightarrow%202C%28g%29)
![Rate = -\frac{1}{2}\frac{\Delta A}{\Delta t} =-\frac{\Delta B}{\Delta t} = \frac{1}{3}\frac{\Delta C}{\Delta t}](https://tex.z-dn.net/?f=Rate%20%3D%20-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7B%5CDelta%20A%7D%7B%5CDelta%20t%7D%20%3D-%5Cfrac%7B%5CDelta%20B%7D%7B%5CDelta%20t%7D%20%3D%20%5Cfrac%7B1%7D%7B3%7D%5Cfrac%7B%5CDelta%20C%7D%7B%5CDelta%20t%7D)
Part B
![-\frac{1}{2}\frac{\Delta A}{\Delta t} =-\frac{\Delta B}{\Delta t}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7B%5CDelta%20A%7D%7B%5CDelta%20t%7D%20%3D-%5Cfrac%7B%5CDelta%20B%7D%7B%5CDelta%20t%7D)
Given: ![-\frac{\Delta A}{\Delta t} = 0.100\ Ms^{-1}](https://tex.z-dn.net/?f=-%5Cfrac%7B%5CDelta%20A%7D%7B%5CDelta%20t%7D%20%3D%200.100%5C%20Ms%5E%7B-1%7D)
![\frac{1}{2}\frac{0.100}{\Delta t} =-\frac{\Delta B}{\Delta t}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7B0.100%7D%7B%5CDelta%20t%7D%20%3D-%5Cfrac%7B%5CDelta%20B%7D%7B%5CDelta%20t%7D)
= 0.0500 M s^-1
Part C
![-\frac{\Delta B}{\Delta t} =\frac{1}{3}\frac{\Delta C}{\Delta t}](https://tex.z-dn.net/?f=-%5Cfrac%7B%5CDelta%20B%7D%7B%5CDelta%20t%7D%20%3D%5Cfrac%7B1%7D%7B3%7D%5Cfrac%7B%5CDelta%20C%7D%7B%5CDelta%20t%7D)
![-\frac{\Delta B}{\Delta t} =\frac{1}{3}\frac{\Delta C}{\Delta t}](https://tex.z-dn.net/?f=-%5Cfrac%7B%5CDelta%20B%7D%7B%5CDelta%20t%7D%20%3D%5Cfrac%7B1%7D%7B3%7D%5Cfrac%7B%5CDelta%20C%7D%7B%5CDelta%20t%7D)
![0.0500 = \frac{1}{3}\frac{\Delta C}{\Delta t}](https://tex.z-dn.net/?f=0.0500%20%3D%20%5Cfrac%7B1%7D%7B3%7D%5Cfrac%7B%5CDelta%20C%7D%7B%5CDelta%20t%7D)
![\frac{\Delta C}{\Delta t} = 3 \times 0.0500 = 0.15 M s^{-1}](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20C%7D%7B%5CDelta%20t%7D%20%3D%203%20%5Ctimes%200.0500%20%3D%200.15%20M%20s%5E%7B-1%7D)
C - If two people pull on it in opposite directions it stretches. Then when they let go it returns to it original size and shape