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enyata [817]
3 years ago
8

Helium gas in a balloon occupies 2.5 L at 300.0 K. The balloon is dipped into liquid nitrogen that is at a temperature of 77.0 K

. What will be the volume of the helium in the balloon at the lower temperature?
A. 0.642 L
B. 1.560 L
C. 9.740 L
D. 9240.0 L
Chemistry
1 answer:
Rom4ik [11]3 years ago
7 0

Answer:

A. 0.641 L

Explanation:

<em>Given data:</em>

V1 = 2.5 L

T1 = 300.0 K

T2= 77.0 K

<em>To find: </em>

V2= ?

<em>Formula :</em>

By using Charles’ Law

\frac{V_1}{T_1}  = \frac{V_2}{T_2}

\frac{V_1}{T_1} . {T_2}  = {V_2}

<em>Calculation:</em>

V2 = 2.5 L x 77.0 K / 300.0 K

    = 192.5 / 300.0 k

V2    = 0.641 L

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g A gas is compressed in a cylinder from a volume of 20.0 L to 2.0 L by a constant pressure of 10.0 atm. Calculate the amount of
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Answer:

The amount of work done on the system is 18234 J and the final positive sign means that this work corresponds to an increase in internal energy of the gas.

Explanation:

Thermodynamic work is called the transfer of energy between the system and the environment by methods that do not depend on the difference in temperatures between the two. When a system is compressed or expanded, a thermodynamic work is produced which is called pressure-volume work (p - v).

The pressure-volume work done by a system that compresses or expands at constant pressure is given by the expression:

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  • W system: Work exchanged by the system with the environment. Its unit of measure in the International System is the joule (J)
  • p: Pressure. Its unit of measurement in the International System is the pascal (Pa)
  • ∆V: Volume variation (∆V = Vf - Vi). Its unit of measurement in the International System is cubic meter (m³)

In this case:

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Replacing:

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