Explanation:
It is given that two loads have 0.75 Ampere current each. And, they contain 2500 milli ampere per hour Ni-Cd battery.
As both the loads are connected in parallel. Hence, total current will be calculated as follows.
I = 
= 0.75 A + 0.75 A
= 1.5 A
= 
= 1500 mA
Relation between time and capacity of battery is as follows.
Capacity = Current × time (in hour)
therefore, time = 
= 
= 1.667 hr
Thus, we can conclude that the battery provide power to the load up to 1.667 hours.
The law of conservation of energy states that energy is never created or destroyed only converted.
Answer:- 27.7 grams of 
are produced.
Solution:- The balanced equation is:
let's convert the grams of each reactant to moles and calculate the grams of the product and see which one gives least amount of the product. This least amount would be the answer as the least amount we get is from the limiting reactant.
Molar mass of ![Pb(NO_3)_2 = 207.2+2(14.01)+6(16) = 331.22 gram per molmolar mass of NaI = 22.99+126.90 = 149.89 gram per molMolar mass of [tex]PbI_2](https://tex.z-dn.net/?f=Pb%28NO_3%29_2%20%3D%20207.2%2B2%2814.01%29%2B6%2816%29%20%20%3D%20331.22%20gram%20per%20mol%3C%2Fp%3E%3Cp%3Emolar%20mass%20of%20NaI%20%3D%2022.99%2B126.90%20%3D%20149.89%20gram%20per%20mol%3C%2Fp%3E%3Cp%3EMolar%20mass%20of%20%5Btex%5DPbI_2)
= 207.2+2(126.90) = 461 gram per mol
let's do the calculations for the grams of the product for the given grams of each of the reactant:
= 
= 
From above calculations, NaI gives least amount of , so the answer is, 27.7 g of are produced.
To solve this we assume that the hydrogen gas is an
ideal gas. Then, we can use the ideal gas equation which is expressed as PV =
nRT. At a constant pressure and number of moles of the gas the ratio T/V is
equal to some constant. At another set of condition of temperature, the
constant is still the same. Calculations are as follows:
T1 / V1 = T2 / V2
V2 = T2 x V1 / T1
V2 = (100 + 273.15) K x 2.50 L / (-196 + 273.15) K
<span>V2 = 12.09 L</span>
Therefore, the volume would increase to 12.09 L as the temperature is increased to 100 degrees Celsius.
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Answer:
V₂ = 530.5 mL
Explanation:
Given data:
Initial temperature = 20.0°C
Final temperature = 40.0 °C
Final volume = 585 mL
Initial volume = ?
Solution:
Initial temperature = 20.0°C (20+273 = 293 K)
Final temperature = 40.0 °C (40+273 = 323 K)
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₁ = V₂T₁ /T₂
V₂ = 585 mL × 293 K / 323 K
V₂ = 171405 mL.K / 323 K
V₂ = 530.5 mL
