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rosijanka [135]
3 years ago
14

A car radio draws 0.18 A of current in the autos 12-V electrical system. (a) How much electric power does the radio use?

Physics
1 answer:
Lera25 [3.4K]3 years ago
8 0

Answer:

Explanation:

a) Electric Power = V X I ,  where V is potential difference  and I is current

= 12 x .18 =2.16 Watt .

b) Resistance = volt / current ( ohm's Law )

Resistance = 12/0.18 = 66.67 ohm.

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Since you've determined that the power supply is a 700W dual rail, what does that make the maximum output power?
inysia [295]

700 makes the maximum output power.

<u>Explanation:</u>

In physics, power is the rate of doing work or of transferring heat, i.e. the amount of energy transferred or converted per unit time. The output power of a motor is the product of the torque that the motor generates and the angular velocity of its output shaft.

A joule is equal to one Newton-meter, which is the amount of work needed to move a 1 Newton force a distance of 1 meter. When you divide work by time, you get power, measured in units of joules per second. This is also called a Watt. 1 Watt = 1 Joule Sec. This is the formula to calculate output power.

6 0
3 years ago
A bus contains a 1440 kg flywheel (a disk that has a 0.63 m radius) and has a total mass of 10200 kg. Calculate the angular velo
CaHeK987 [17]

Answer:\omega =93.51 rad/s

Explanation:

Given

mass of Flywheel m_1=1440 kg

mass of bus m_b=10200 kg

radius of Flywheel r=0.63 m

final speed of bus v=21 m/s

Conserving Energy i.e.

0.9(Rotational Energy of Flywheel)= change in Kinetic Energy of bus

Let \omegabe the angular velocity of Flywheel

0.9\cdot \frac{I\omega ^2}{2}=\frac{m_bv^2}{2}

I=moment\ of\ Inertia =mr^2=1440\cdot 0.63^2=571.536 kg-m^2

0.9\cdot \frac{571.536\cdot \omega ^2}{2}=\frac{10200\cdot 21^2}{2}

\omega ^2=21^2\times \frac{10200}{0.9\times 571.536}

\omega =21\times 4.45=93.51 rad/s

8 0
3 years ago
In what circuit does an increase in resistance mean an increase in current?
skad [1K]
I think in parallel circuits.
6 0
2 years ago
Plzz answer the question.
Aleksandr [31]
Ur answer is 3 and i'm sure of it 
8 0
3 years ago
The majority of the sun's energy that reaches Earth is __________. View Available Hint(s) The majority of the sun's energy that
Lera25 [3.4K]

Answer:

not captured for use by living things

Explanation:

The sun is a star with a high radiation and most of(around 55-67%) the radiation that reaches the earth is usually reflected back. The earth cannot use all the energy that reaches the earth. It uses almost around 15-30%

3 0
3 years ago
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