Answer:
6
Explanation:
Add 10+7+3+4 and then divide your answer by 4
2^4/2^7 = 16/128 = 0.125
(1/2)^3= 0.125
1/8= 0.125
a and f are equivalent
Answer:
The distance s of how far the ball will go at the highest setting = 2.25m
Explanation:
Let consider x to be the representative of the compression and the distance to be s
Recall that:

By cross multiplying




Thus, for the first setting
x = 1 , s = 0.25
for the second setting
x = 2, s = 1
1 = 0.25A + B --- (1)
4 = A + B ----- (2)
From (1); let B = 1 - 0.25A and substitute it into (2)
4 = A + 1 - 0.25 A
4 - 1 = A - 0.25 A
3 = 0.75 A
A = 3/0.75
A = 4
From (2)
4 = A + B
4 = 4 + B
B = 4 - 4
B = 0
Therefore, for the highest setting, where x = 3
Then :
will be:
3² = 4s + 0
9 = 4s
s = 9/4
s = 2.25 m
∴
The distance s of how far the ball will go at the highest setting = 2.25m
Density = mass / volume. Mass = 1587g. Volume = 4.5cm x 5.2cm x 6cm = 140.4 cubic-cm. Mass/volume = 1587/140.4 = 11.3 g/cm^3.