The cost of running the lightbulb A for 30 days at 0.110 per KWh is 1.98
<h3>How to determine the energy </h3>
We'll beging by calculating the energy used by lightbulb A. This can be obtained as follow:
- Power (P) = 25 watts = 25 / 1000 = 0.025 KW
- Time (t) = 30 days = 30 × 24 = 720 h
- Energy (E) =?
E = Pt
E = 0.025 × 720
E = 18 KWh
<h3>How to determine the cost for running the bulb for 30 days</h3>
The cost of running the bulb for 30 days can be obtained as follow:
- Cost per KWh = 0.11
- Energy (E) = 18 KWh
- Cost =?
Cost = energy × Cost per KWh
Cost = 18 × 0.11
Cost = 1.98
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Answer:
True
Explanation:
A wave is generated as a result of oscillations which creates disturbances in the medium and these disturbances termed as waves propagates or travels from one point to another.
Waves can be classifies as:
Mechanical waves which requires material medium for their propagation
Electromagnetic waves which do not require any material medium to propagate.
A wave travels at a specific velocity depending on the type of the medium in which it propagates.
Answer:
0.0327 m
Explanation:
m = 2 kg
ω = 24 rad/s
A = 0.040 m
Let at position y, the potential energy is twice the kinetic energy.
The potential energy is given by
U = 1/2 m x ω² x y²
The kinetic energy is given by
K = 1/2 m x ω² x (A² - y²)
Equate both the energies as according to the question
1/2 m x ω² x y² = 2 x 1/2 m x ω² x (A² - y²)
y² = 2 A² - 2 y²
3y² = 2A²
y² = 2/3 A²
y = 0.82 A = 0.82 x 0.040 = 0.0327 m
-- Any object has gravitational potential energy relative to any place
lower than where the object is. The stove in the kitchen has potential
energy relative to the basement floor.
-- If an object is not moving, then it has no kinetic energy. The stove has
no kinetic energy unless you throw it or drop it out of a window.
The voltage across an inductor ' L ' is
V = L · dI/dt .
I(t) = I(max) sin(ωt)
dI/dt = I(max) ω cos(ωt)
V = L · ω · I(max) cos(ωt)
L = 1.34 x 10⁻² H
ω = 2π · 60 = 377 /sec
I(max) = 4.80 A
V = L · ω · I(max) cos(ωt)
V = (1.34 x 10⁻² H) · (377 / sec) · (4.8 A) · cos(377 t)
<em>V = 24.25 cos(377 t)</em>
V is an AC voltage with peak value of 24.25 volts and frequency = 60 Hz.
