An acceleration of a freely falling body (9.8m/s^2) to ft/s^2

If you stay on earth while a friend races off in a rocket at a speed close to the speed of light, then according to special rela

Natasha_Volkova [10]

Answer:

D-slower than the clock on the rocket.

Explanation:

In 1905, Albert Einstein devised the theory that states that laws of physics are the same for all non-accelerating observers, and that the speed of light in a vacuum was independent of the motion of all observers. This conclusion is generally referred to as the theory of special relativity. It defined an entirely new framework for physics as well as proposed new concepts of space and time.

He discovered that space and time were interwoven into a single continuum known as space-time. According to him, events that occur at the same time for one observer could occur at different times for another, hence the answer.

4 0

3 years ago

A vertical spring gun is used to launch balls into the air. If the spring is compressed by 4.9 cm, the ball of mass 5.5 g is lau

AleksandrR [38]

We know, by conservation of energy :

$\dfrac{kx^2}{2}=mgh$

Therefore,

$\dfrac{x_1^2}{x_2^2}=\dfrac{h_1}{h_2}$

Putting given values, we get :

$\dfrac{x_1^2}{x_2^2}=\dfrac{h_1}{h_2}\\\\\dfrac{4.9^2}{x_2^2}=\dfrac{50.2}{2\times 50.2}\\\\x_2^2=2\times 4.9^2\\\\x_2 = 4.9\times \sqrt{2}\\\\x_2=6.93\ cm$

Therefore, the spring be compressed to 6.93 cm to send the ball twice as high.

Hence, this is the required solution.

6 0

2 years ago

Most comets have short periods and orbit close to the ecliptic plane. (T/F)

Lapatulllka [165]

Answer:

False

Explanation:

Most comets are located outside the solar system, in part of the cloud that originated from dust and gas that has remained virtually untouchable for billions of years. The orbit of these comets can reach the order of a light year. Thus, they are called long-period comets.

3 0

3 years ago

The center of the Hubble space telescope is 6940 km from Earth’s center. If the gravitational force between Earth and the telesc

Law Incorporation [45]

The gravitational force between two objects is given by:
$F=G \frac{m_1 m_2}{r^2}$
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is the separation between the two objects

The distance of the telescope from the Earth's center is $r=6940 km=6.94 \cdot 10^6 m$ , the gravitational force is $F=9.21 \cdot 10^4 N$ and the mass of the Earth is $m_1=5.98 \cdot 10^{24} kg$ , therefore we can rearrange the previous equation to find m2, the mass of the telescope:
$m_2 = \frac{Fr^2}{Gm_1}= \frac{(9.21 \cdot 10^4 N)(6.94\cdot 10^6)^2}{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})} =11121 kg$

6 0

3 years ago

Read 2 more answers

CAN SOMEONE HELP ME PLEASE ASAP

Lady_Fox [76]

The third choice is correct

8 0

3 years ago

Read 2 more answers