Plzzzz help me this is due today. only need help with these two questions and the element is oxygen.

A gymnast does a one-arm handstand. The humerus, which is the upper arm bone between the elbow and the shoulder joint, may be ap

igor_vitrenko [27]

Answer:

$= 5.241 \times 10^{-5} m$

Explanation:

Given:

Length of cylinder is, L = 0.27 m

Outer radius of cylinder is, r_out = 1.12×10^{-2} m

Inner radius of cylinder is, r_in = 3.9×10^{-3} m

Mass of person, m = 60 kg

Young's modulus , Y = 9.4×10^9 N/m2

(a)

Compressional strain of humerous is,

$Strain = \frac{Stress}{Young's\ modulus}$

$\frac{\Delta L}{L_0} = \frac{\frac{F}{A}}{Y}$

$= \frac{(mg)}{\pi(r_out^2 - r_in^2 )Y}$

$= \frac{(60 kg)(9.8 m/s2 )}{(\pi)[( 1.12\times 10^{-2})^2 - (3.9\times 10^{-3} m)^2] (9.4\times 10^9 N/m2 )}[tex] [tex]= 1.80\times 10^{-4} m$

(b) Let assume that humerous is compressed by ΔL

Since, strain = ΔL/L0

$(1.80 \times 10^{-4} m) = ΔL / 0.29 m$

Thus,

$ΔL = (4.56 \times 10^{-4} m)(0.29 m)$

$= 5.241 \times 10^{-5} m$

7 0

3 years ago

Joey drives his Skidoo 13 kilometres north. He stops for lunch and then drives 10kilometres south. What distance did he cover? W

olganol [36]

Answer:

Total distance covered (scalar quantity) = 23 km

Displacement (vector quantity) = 3 km north from the original starting point

Explanation:

Since he drove 13 km north and then 10 km south, the total distance he cover in his drive was: 13 km + 10 km = 23 km

On the other hand, his displacement was 3 km north from where he started.

7 0

3 years ago

The average lifetime of a poodle dog is 13.0 years. How fast is it traveling, u, relative to an observer who measures the averag

bogdanovich [222]

Answer:

The speed is 0.97 c.

Explanation:

Given that,

Dilated time t'= 50.0 years

Rest time t = 13.0 years

We need to calculate the speed

Using formula of time dilation

$t'=\dfrac{t}{\sqrt{1-\dfrac{v^2}{c^2}}}$

Where, t' = change in time

t = rest time

v = velocity

c = speed of light

Put the value into the formula

$50.0=\dfrac{13.0}{\sqrt{1-\dfrac{v^2}{(3\times10^{8})^2}}}$

$v^2=\dfrac{(13)^2\times(c)^2-(c)^2\times50^2}{50^2}$

$v^2= 0.9324c^2$

$v=0.97c$

Hence, The speed is 0.97 c.

6 0

3 years ago

a technician connects the red lead of a voltmeter to the b+ [output] terminal of an ac generator and the black lead to the batte

stealth61 [152]

Answer:

He is testing for voltage drop (voltage drop test)

Explanation:

Connecting the red lead of a voltmeter to the B+ output to an ac generator and black lead to a battery +ve terminal measures the voltage drop in the circuit when the engine is turned ON and all electrical accessories too.

with this he knows if the alternator is charging the battery.

8 0

4 years ago

A source emits sound with a frequency of 860 Hz. It is moving at 20.0 m/s toward a stationary reflecting wall. If the speed of s

Galina-37 [17]

Answer:

$f_o=860\ Hz$

Explanation:

Given:

original frequency of sound wave, $f=860\ Hz$

speed of the sound source, $v_s=20\ m.s^{-1}$

original speed of sound wave from the source, $s=343\ m.s^{-1}$

<u>According to the Doppler's effect:</u>

$\frac{f_s}{f_o} =\frac{s+v_s}{s-v_o}$

The sound is reflected from the wall and the source is moving towards the wall and observer is also riding the same source.

The velocity of the observer, $v_o=-20\ m.s^{-1}$

$\frac{860}{f_o} =\frac{s+20}{s-(-20)}$

$f_o=860\ Hz$

3 0

3 years ago

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