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3 years ago

Which nuclear emission has the greatest penetrating power

Physics

1 answer:

velikii [3]3 years ago

3 0

Answer:

<em><u>Gamma γ radiations has the highest penetrating power,</u></em> of all the nuclear emissions.

Explanation:

The three major types of nuclear emissions are <em>alpha (α), beta (β)</em> and <em>gamma </em>radiations. Of all three, gamma (Υ) radiations have the highest penetrating power (only shielded by lead and concrete), owing to its lack of mass and charge.

It also has a low ionization power and so does not interact well with matter. IT has vast application in cancer treatment and sterilization mechanism.

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Por una tubería de 0.06 m de diámetro circula agua con una velocidad desconocida, al llegar a la parte estrecha de la tubería de

Vesnalui [34]

Answer:

La velocidad con la que se desplaza el agua antes de llegar a la parte estrecha de la tubería es 1.156 $\frac{m}{s}$

Explanation:

La ecuación de continuidad es simplemente una expresión matemática del principio de conservación de la masa. Este principio establece que la masa de un objeto o colección de objetos nunca cambia con el tiempo.

La ecuación de continuidad es la relación que existe entre el área y la velocidad que tiene un fluido en un lugar determinado y dice que el caudal de un fluido es constante a lo largo de un circuito hidráulico.

En otras palabras, la ecuación de continuidad se basa en que el caudal (Q) del fluido ha de permanecer constante a lo largo de toda la conducción. Cuando un fluido fluye por un conducto de diámetro variable, su velocidad cambia debido a que la sección transversal varía de una sección del conducto a otra.

Entonces, siendo el caudal es el producto de la superficie de una sección del conducto por la velocidad con que fluye el fluido, en dos puntos de una misma tubería se cumple:

Q1=Q2

A1*v1= A2*v2

donde:

A es la superficie de las secciones transversales de los puntos 1 y 2 del conducto.

v es la velocidad del flujo en los puntos 1 y 2 de la tubería.

Siendo $A=pi*r^{2} =pi*(\frac{D}{2} )^{2} =\frac{pi*D^{2} }{4}$ , donde pi es el número π, r es el radio del conducto y D el diámetro del conducto, entonces:

$\frac{pi*D1^{2} }{4}*v1=\frac{pi*D2^{2} }{4}*v2$

En este caso:

D1: 0.06 m
v1: ?
D2: 0.04 m
v2: 2.6 m/s

Reemplazando:

$\frac{pi*(0.06m)^{2} }{4}*v1=\frac{pi*(0.04m)^{2} }{4}*2.6\frac{m}{s}$

Resolviendo:

$v1=\frac{\frac{pi*(0.04m)^{2} }{4}*2.6\frac{m}{s}}{\frac{pi*(0.06m)^{2} }{4}}$

$v1=\frac{(0.04m)^{2} }{(0.06m)^{2} }*2.6\frac{m}{s}$

v1= 1.156 $\frac{m}{s}$

<u><em>La velocidad con la que se desplaza el agua antes de llegar a la parte estrecha de la tubería es 1.156 </em></u> $\frac{m}{s}$ <u><em></em></u>

8 0

3 years ago

(1) Viewers of Star Trek hear of an antimatter drive on the Starship Enterprise. One possibility for such a futuristic energy so

malfutka [58]

Solution :

The relationship between the strength of magnetic field and the radiusof a charged particle's path is obtained through Newton's second law, which is given by :

F = ma

F = qvB and $a=\frac{v^2}{r}$

Substituting these values in the second law of Newton,

$qvB=\frac{mv^2}{r}$

Now solving for B, we get:

$B = \frac{mv}{rq}$

$=\frac{(1.67 \times 10^{-27})(5 \times 10^{7})}{2\times 1.6 \times 10^{-19}}$

= 0.261 T

The field strength can be obtained by using the technology of today.

7 0

3 years ago

While in europe, if you drive 125 km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per lite

Ymorist [56]

First we need to write the data given in the problem.
Given Data
Distance per day = 125km
Gas cost =1.10 Eu per liter
Car mileage= 37.0 mil/gal
1 Eu= 1.26$
Find
1 week expenditure on Gas =?

Solution
Distance in one week = 125 kmx 7 = 875 km or 543.7 miles
Gas consumed in one week = 543.7/37 = 14.694 gal or 52.99 litre

Answer
Cost of Gas per week = 52.99 x 1.10 = 58.28 Eu or 73.44$

Regards

8 0

3 years ago

How long does it take light from a camera to travel to the face of someone standing 7 meters away?

mestny [16]

The time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s

Speed is simply defined as the distance travelled per unit time. Mathematically, it is expressed as:

<h3>Speed = distance / time </h3>

With the above formula, we can obtain the time taken for the light to travel from the camera to someone standing 7 m away. This can be obtained as follow:

Distance = 7 m

Speed of light = 3×10⁸ m/s

Time = Distance / speed

Time = 7 / 3×10⁸

Therefore, the time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s

Learn more: brainly.com/question/14988345

8 0

2 years ago

Kevin jumps straight up in the air to a height of 1 meter.At the top of his jump, he has potential energy of 1,000 joules.Answer

Llana [10]

Gravitational potential energy can be given by the equation
PE = mgh
where m is the mass,
g is the gravitational constant 9.81 or 10 depending on rounding
and h is the height

well weight is a force equiavlent to
W= m*g

so comparing that to the potential energy equation, divide the potential energy by the height and you will get weight in Newtons

3 0

3 years ago