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Elena-2011 [213]
3 years ago
15

A ball is thrown horizontally from the top of a building 14.9 m high. The ball strikes the ground at a point 107 m from the base

of the building. The acceleration of gravity is 9.8 m/s 2 . Find the time the ball is in motion.Find the initial velocity of the ball. Answer in units of m/sFind the x component of its velocity just be- fore it strikes the ground.Answer in units of m/sFind the y component of its velocity just be- fore it strikes the ground.Answer in units of m/s
Physics
1 answer:
umka2103 [35]3 years ago
8 0

Answer:

1) t=1.743 sec

2)Vo=61.388  m/sec

3)the x component of its velocity just be- fore it strikes the ground is the same as the  initial velocity of the ball that is=61.388  m/sec

4)Vf=17.08 m/s

Explanation:

1)From second equation of motion we get

h=Vit+(1/2)gt^2

here in case(a): Vi=0 m/s,h=14.9m,,put these values in above equation to find the time the ball is in motion

14.9=(0)*t+(1/2)(9.8)t^2

t^2=14.9/4.9

t^2=3.040 sec

t=1.743 sec

2) s=Vo*t

Putting values we get

107=Vo*1.743

Vo=61.388  m/sec

3)the x component of its velocity just be- fore it strikes the ground is the same as the  initial velocity of the ball that is=61.388  m/sec

4)From third equation of motion we know that

Vf^2-Vi^2=2gh

here Vi=0 m/s,h=14.9 m

Vf^2=Vi^2+2gh=0+2(9.8)(14.9)

Vf^2=292.04

Vf=17.08 m/s

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the car starts from rest at s=0 and increases its speed at at=4m/s^2. Determine the time when the magnitude of acceleration beco
dem82 [27]

Answer:

<em>Time =  5 seconds</em>

<em>Distance = 50 meters</em>

Explanation:

<u>Constantly Accelerated Motion</u>

When the velocity of a moving object changes at a constant rate, called acceleration, the velocity changes in same amounts in the same times. The question has a mistake when asking when the acceleration is 20 m/s. If the acceleration is constant, the only variable that can change to that value is the velocity. The equation to calculate the speed is

v_f=v_o+a.t

And the distance s is

\displaystyle s=v_o.t+\frac{gt^2}{2}

Given the object starts from rest, vo=0 and vf=20 m/s at a=4\ m/s^2. We compute t

\displaystyle t=\frac{v_f-v_o}{a}=\frac{20-0}{4}

\boxed{t=5\ sec}

Now we compute s

\displaystyle s=0+\frac{4\times 5^2}{2}

\boxed{s=50\ m}

5 0
2 years ago
An aeroplane accelerates from rest to 65 m/s for take-off. It travels for
Virty [35]

Answer:

1.76m/s²

Explanation:

Given parameters:

Initial velocity  = 0m/s

Final velocity  = 65m/s

Distance traveled  = 1200m

Unknown:

Acceleration  = ?

Solution:

This is linear velocity and we apply the appropriate motion equation to solve this problem.

      V²  = U² + 2as

S is the distance

u is the initial velocity

V is the final velocity

a is the acceleration

Now, insert the parameters and solve;

             65²  =  0² + 2 x a x 1200

             4225 = 2400a

                  a  = 1.76m/s²

5 0
3 years ago
A helicopter is ascending vertically. a passenger accidentally drops her wallet out the sides of the helicopter when it is 160 m
Advocard [28]

Answer:

(E)56.0 m/s

Explanation:

Height =h=-160 m

Because the wallet moving in downward direction

Time=t=7 s

Final speed of wallet=v=0

We have to find the speed of helicopter ascending  at the moment when the passenger let go of the wallet.

v^2-u^2=2gh

Where g=9.8 m/s^2

Substitute the values

0-u^2=2(-160)\times 9.8

u^2=3136

u=\sqrt{3136}=56m/s

Option (E) is true

8 0
3 years ago
Now assume that Eq. 6-14 gives the magnitude of the air drag force on the typical 20 kg stone, which presents to the wind a vert
chubhunter [2.5K]

Answer:

362.41 km/h

Explanation:

F = Force

m = Mass = 84 kg

g = Acceleration due to gravity = 9.81 m/s²

C = Drag coefficient = 0.8

ρ = Density of air = 1.21 kg/m³

A = Surface area = 0.04 m²

v = Terminal velocity

F = ma

F=\frac{1}{2}\rho CAv^2\\\Rightarrow mg=\frac{1}{2}\rho CAv^2\\\Rightarrow v=\sqrt{2\frac{mg}{\rho CA}}\\\Rightarrow v=\sqrt{2\frac{20\times 9.81}{1.21\times 0.8\times 0.04}}\\\Rightarrow v=100.66924\ m/s

Converting to km/h

100.66924\times 3.6=362.41\ km/h

The terminal velocity of the stone is 362.41 km/h

5 0
2 years ago
Read 2 more answers
Need help with this science!!
noname [10]
Lol, I remember I helped my sister with this question but anyways, the card flew because of inertia and the quarter fell in the glass because of gravity :).
3 0
3 years ago
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