Answer:
no of cycle required is 1885.3
Explanation:
given data
thermal energy Q1 = 75 J
thermal energy Q2 = 115 J
load = 3454 kg
distance = 27 m
steady rate = 52.5 mm/s
to find out
How many cycles of the engine are need
solution
we find here first work done that is express as
work done W = Q2 - Q1 ..................1
put here all these value
W = 115 - 75
work done is 40 J
so energy required is
Energy required E = m×g×h ..................2
put here value
E = 285 × 9.8 × 27
energy required = 75411 J
so here no of cycle is
no of cycle = energy required / work done
put here value
no of cycle required = 75411 / 40
so no of cycle required is 1885.3
Answer:
How do organisms use the raw materials they ingest from the environment?
All living entities require energy to sustain and maintain life. Plants and animals slightly differ in their raw material intake for survival. The raw materials required by an organism will vary depending on the complexity of the organism and its environment. All animals take in food, water and oxygen as raw material from the outside. As for plants, they take in carbon dioxide, water and sunlight to synthesize their own food in the presence of chlorophyll.
Outside raw materials used by an organism
Various outside raw materials used by an organism are as follows:
Food as source of energy.
Oxygen for breakdown of food to obtain energy
Water for proper digestion of food and other functions inside the body.
Answer:
The value is
Explanation:
From the question we are told that
The length is 
The radius of the the solenoid is 
The number of turns per meter is 
The current through the solenoid is 
The current through the segment is 
Generally the magnetic force is mathematically represented as

At maximum 
So

Here B is the magnetic field is mathematically represented as

Here
is the permeability of free space with value

So

=> 
So

Answer:
400 N
Explanation:
Change of Kinetic Energy to Friction Wok
∆KE = W
½ x m x (v(5)² - v(3)²) = f x d
½ x 500 x (5² - 3²) = f x 10
250 x (25 - 9) = f x 10
25 x 16 = f
f = 400 N