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Juliette [100K]
3 years ago
11

Solve 5kx+6=7kx for x

Mathematics
2 answers:
artcher [175]3 years ago
8 0

Answer:

The answer is 3/k .

Step-by-step explanation:

First you have to move all the related terms to one side :

5kx + 6 = 7kx

6 = 7kx - 5kx

2kx = 6

Next, you have to solve it :

x = 6 \div 2k

x = 3 \div k

x =  \frac{3}{k}

Oksanka [162]3 years ago
7 0

Answer:

7kx-5kx=6

2kx=6

x=3/k

Step-by-step explanation:

ur welcome my guy

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Would it be division or multiplication
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H(x)=-x^2-4 and I(x)=2x+3<br> H(I(s))
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4 years ago
Use the following table for questions 11-13.A baseball manager believes a linear relationship exists between the number of Home
slamgirl [31]

The regression equation of Y on X is given by the following formula:

Y-\bar{Y}=b_{yx}(X-\bar{X})

Where byx is given by the formula:

b_{yx}=\frac{N\sum^{}_{}XY-\sum^{}_{}X\sum^{}_{}Y}{N\sum^{}_{}X^2-(\sum^{}_{}X)^2}

Where N is the number of values (N=8). We need to find the sum of X values, the sum of Y values, the average of X, the average of Y, the sum of X*Y and the sum of X^2.

The table of values is:

The values we need to know are on the following table:

By replacing the known values in the formula we obtain:

\begin{gathered} b_{yx}=\frac{8\cdot26125-167\cdot995}{8\cdot4649-(167)^2} \\ b_{yx}=\frac{209000-166165}{37192-27889} \\ b_{yx}=\frac{42835}{9303} \\ b_{yx}=4.6 \end{gathered}

Now, the average of X and Y is the sum divided by N, then:

\begin{gathered} \bar{X}=\frac{167}{8}=20.87 \\ \bar{Y}=\frac{995}{8}=124.37 \end{gathered}

Replace these values in the formula and find the regression equation as follows:

\begin{gathered} Y-124.37=4.6(X-20.87) \\ Y-124.37=4.6X-4.6\cdot20.87 \\ Y=4.6X-96.11+124.37 \\ Y=4.6X+28.26 \end{gathered}

The answer is a) y=4.6x+28.26

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