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Gre4nikov [31]
3 years ago
10

Identify the inverse variation and graph in which y = 0.75 when x = 4.

Mathematics
1 answer:
TiliK225 [7]3 years ago
7 0

Answer:

y=3/x  or yx=3

The graph in the attached figure

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form y*x=k or y=k/x

so

in this problem we have

y=0.75 when x=4

Find the value of k

y*x=k

k=0.75*4=3

The equation is equal to

y=3/x

using a graphing tool

see the attached figure

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Write the exponential function for each table of values. Remember the function y = a(b)*
almond37 [142]

Answer:

Step-by-step explanation:

This is really simple once you get the hang of it. Promise. Remember this:

IF YOU HAVE THE OPPORTUNITY TO CHOOSE A POINT FROM THE TABLE WHERE X = 0, THEN DO IT!

This gives you the a value in your equation and you don't have to solve for it. I'll show you how this looks in the first table of values and then we won't have to do it going forward.

I'm using the coordinates (0, 1) and (1, .5) from the first table. Filling in the equation with the first set of coordinates:

1=a(b)^0 and since anything to the 0 power is 1, we know a = 1 (this happens every time we have a coordinate in an exponential table where the x value is 0. a always equals whatever y is!)

Now that we know a = 1, we use that along with the next coordinate pair and solve for b:

.5=1(b)^1 which simplifies to

.5 = b and the equation is

y=1(.5)^x

For the next table use the coordinate (0, 50) and 1, 25). From the above explanation, I know that a = 50 (because x = 0). Use that along with the next coordinate pair to solve for b:

25=50(b)^1 which simplifies to

b = .5 and the equation is

y=50(.5)^x

Lastly, use the points (0, 192) and (1, 768) and we know that a = 192; and it follows that

768=192(b)^1 so

b = 4 and the equation is

y=192(4)^x

The first 2 of these are exponential decay because the number inside the parenthesis is less than 1 but greater than 0; the last one is exponential growth since the number inside the parenthesis is greater than 1. That's how you can tell.

8 0
3 years ago
Simplify the following expression completely.<br> x^2 + 13x + 36<br> x^2 – 3x – 28
Volgvan

Answer:

37x^2+10x-28

Step-by-step explanation:

use ma.thway it will give you the answer to any math problem

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3 years ago
What is the distance between (5,-2) and (5,3)
Mumz [18]

Answer:

B-1

Step-by-step explanation:


6 0
3 years ago
The distribution of actual weights of 8-oz chocolate bars produced by a certain machine is normal with mean 7.9 ounces and stand
fgiga [73]

Answer:

91.60% probability that the average weight of a bar in a simple random sample of three of these chocolate bars is between 7.76 and 8.09 ounces

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 7.9, \sigma = 0.16, n = 3, s = \frac{0.16}{\sqrt{3}} = 0.0924

What is the probability that the average weight of a bar in a simple random sample of three of these chocolate bars is between 7.76 and 8.09 ounces?

This is the pvalue of Z when X = 8.09 subtracted by the pvalue of Z when X = 7.76. So

X = 8.09

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{8.09 - 7.9}{0.0924}

Z = 2.06

Z = 2.06 has a pvalue of 0.9803

X = 7.76

Z = \frac{X - \mu}{s}

Z = \frac{7.76 - 7.9}{0.0924}

Z = -1.52

Z = -1.52 has a pvalue of 0.0643

0.9803 - 0.0643 = 0.9160

91.60% probability that the average weight of a bar in a simple random sample of three of these chocolate bars is between 7.76 and 8.09 ounces

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4 years ago
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