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Kamila [148]
3 years ago
7

What elements are dull,brittle and poor conductors

Physics
1 answer:
Artemon [7]3 years ago
8 0

Answer:

I think the answer is Nonmetal...

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A science teacher tells her class that their final project requires students to measure a specific variable and determine the ve
iogann1982 [59]

Answer:

Yes

Explanation:

The velocity measured by Jennifer and Johnny is

v_m = 34.87 m/s

The actual velocity is

v=34.15 m/s

We can calculate the % error of the students measurement as follows:

Err = \frac{v_m - v}{v}\cdot 100 = \frac{34.87 m/s-34.15 m/s}{34.15 m/s}\cdot 100 =0.021 \cdot 100 = 2.1 \%

Which is lower than the 2.5% maximum error required, so the two students will pass the test.

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A composite load consists of three loads connected in parallel. One draws 100 W at a PF of 0.92 lagging, another takes 250 W at
fenix001 [56]

Answer:

a) I_{RMS} = 4.79 A

b) PF = 0.908

Explanation:

Get the reactive powers for each of the loads:

Reactive power = Real Power * tanθ

For load 1

Active power, P₁ = 100 W

Power factor, cos \theta_{1} = 0.92

\theta_{1} = cos^{-1} 0.92\\\theta_{1} = 23.074

Q_{1}= P_{1} tan \theta_{1} \\Q_{1}= 100tan 23.074\\Q_{1}= 42.60 W

For load 2

Active power, P₂ = 250 W

Power factor, cos \theta_{2} = 0.8

\theta_{2} = cos^{-1} 0.8\\\theta_{2} = 36.87

Q_{2}= P_{1} tan \theta_{2} \\Q_{2}= 250tan 36.87\\Q_{2}= 187.5 W

For load 3

Active power, P₃ = 250 W

Power factor, cos \theta_{3} = 1

\theta_{3} = cos^{-1} 1\\\theta_{3} =0

Q_{2}= P_{1} tan \theta_{3} \\Q_{3}= 150tan 0\\Q_{3}= 0 W

Calculate the total reactive power, Q_{net} = 42.6 + 187.5 + 0

Q_{net} = 230.1 W

Calculate the total active power, P_{net} = 100 + 250 + 150 = 500 W

S_{net} = P_{net} + Q_{net} \\S_{net} = 500 + j230.1

P_{net} = IVcos \theta_{net}

\theta_{net} = tan^{-1} \frac{230.1}{500} \\\theta_{net} = 24.712

V = 115 V_{rms}

500 = I_{RMS}  * 115 cos 24.712\\I_{RMS} = 500/104.47\\ I_{RMS} = 4.79 A

b) Power factor of the composite load is cos\theta_{net}

\theta_{net}  = 24.712\\PF = cos 24.712\\PF = 0.908

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hope this helps have a great day!

Explanation:

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