Given:
m(mass of the car)=1134 Kg
u(Initial velocity)=83Km/HR=23m/s
s(distance traveled by the car)=98m
v(final velocity)=0(as it is given the car stops).
Now we know,
v=u+at
Where v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
0=23+at
at=-23
Also
s=ut+1/2(at^2)
s is the distance covered by the car
u is the initial velocity
t is the time necessary for the car to cover a particular distance.
a is the acceleration
Now substituting these values we get
98=23t-1/2(23t)
98=23t-11.5t
11.5t=98
t=8.52secs
Now we have already derived
at=-23
ax8.52=-23
a=-23/8.52
a=-2.75 m/s^2
F=mxa
Where F is the force acting on the car.
m is the mass of the car.
a is the acceleration.
F=1134 x-2.75
F=-3119N
Newton's third law says that for every action, there is an equal and opposite reaction. So if your friend's bumper car, both of you will go flying back at the same force in opposite directions.
Hope this helps.
I think it's 21 that's what I got when I was on that answer
<u>Answer:</u>
<em>The truck is going 40 km/h faster than the speed limit.
</em>
<u>Explanation:</u>
The fixed speed limit = <em>60km/h</em>
distance travelled by the truck = <em>10 km</em>
time taken <em>t=6 minutes</em>
we have convert 6 minutes into hour
<em>1 hour=60 minutes
</em>
<em>1 minute=1/60 hour </em>
<em>6 minute=6/60 hour=1/10 h
</em>
Speed is obtained by dividing distance covered by time.
<em> speed = distance/time = =100 km/h
</em>
<em>difference between the speed of the car and the speed limit</em>
<em>=100-60 = 40km/h
</em>