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Nina [5.8K]
3 years ago
5

2. How many grams of water can be warmed from 25.0°C to 37.0°C by the addition of 8,064 calories?

Chemistry
1 answer:
sertanlavr [38]3 years ago
5 0

Answer:

672 g

Explanation:

We can calculate the mass of water that can be warmed from 25.0°C to 37.0°C by the addition of 8,064 calories using the following expression.

Q = c \times m \times \Delta T

where,

c: specific heat of the water

m: mass

ΔT: change in the temperature

m = \frac{Q}{c \times \Delta T  }  = \frac{8,064cal}{(1cal/g. \° C) \times (37.0 \° C - 25.0 \° C)  } = 672 g

The mass of water that can be warmed under these conditions is 672 grams.

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Among the following options, a valid Lewis structure of __________ cannot be drawn without violating the octet rule.
Murrr4er [49]

Answer:

d. IF3

Explanation:

The Octet rule posits that atoms gain, atom lose, or share electrons in order to have a full valence shell of 8 electrons. This statement occurs when atoms also combine to form molecules until they attain or share eight valence electrons either by losing or gaining eletrons.

From the given options, a valid Lewis structure that cannot be drawn without violating the octet rule is IF3

8 0
3 years ago
A given sample of a gas has a volume of 3 liters at a
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Answer:

B) 12

Explanation:

Given parameters:

Initial volume  = 3L

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Unknown:

Final volume  = ?

Solution:

To solve this problem, we apply Boyle's law which states that "the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".

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A sample of helium gas occupies a volume of 152.0 mL at a pressure of 717.0 mm Hg and a temperature of 315.0 K. What will the vo
kozerog [31]

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0.581 L  or  581 mL

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Write down the amounts you are given.

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V2 = 0.581

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aleksandr82 [10.1K]
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