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lbvjy [14]
3 years ago
7

Which particles give the nucleus its positive charge?

Chemistry
1 answer:
Mnenie [13.5K]3 years ago
6 0

Answer:

protons only

Explanation:

proton is present in the nucleus of atom as sub atomic particle ..

proton has + charge in the it's top as p+..

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An ___is usually a homologous structure that is shared by all organisms in a group~science
Paraphin [41]
A shared derived characteristics is usually a homologous structure, such as a backbone, that is shared by all organisms in a group.
8 0
3 years ago
Draw the orbital notation for the element Boron
Wewaii [24]

Answer:

I can't draw but you could draw 2 electrons in the first orbit and 3 electrons in the second orbit.

Explanation:

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3 years ago
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Which ion is the only negative ion produced by an Arrhenius base in water?
Snowcat [4.5K]
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6 0
3 years ago
How many grams of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O?
shepuryov [24]

Explanation:

Molarity is defined as number of moles per liter of solution.

Mathematically,         molarity = \frac{no. of moles}{Volume (in L) of solution}

It is given that molarity is 0.0800 M and volume is 50.00 mL or 0.05 L.

           molarity = \frac{no. of moles}{Volume of solution in liter}

            0.0800 M = \frac{no. of moles}{0.05 L}

            no. of moles = 1.6 mol

Therefore, molar mass of cupric sulfate pentahydrate is 249.68 g/mol. So, calculate the mass as follows.

                No. of moles = \frac{mass in grams}{molar mass}

             mass in grams = no. of moles \times molar mass of CuSO_{4}.5H_{2}O

                                       = 1.6 mol \times 249.68 g/mol

                                       = 399.488 g

Thus, we can conclude that 399.488 g of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O.

4 0
3 years ago
Propanoic acid fromula<br>​
Romashka [77]

Answer:

C₃H₆O₂

Explanation:

Propionic acid is a colorless liquid with a sharp rancid odor. Produces irritating vapor. (USCG, 1999)

8 0
3 years ago
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