Units of impulse: N • s, kg • meters per second
Explanation:
Impulse is defined in two ways:
1)
Impulse is defined as the product between the force exerted in a collision and the duration of the collision:
where
F is the force
is the time interval
Since the force is measured in Newtons (N) and the time is measured in seconds (s), the units for the impulse are
![[I] = [N][s]](https://tex.z-dn.net/?f=%5BI%5D%20%3D%20%5BN%5D%5Bs%5D)
So,
N • s
2)
Impulse is also defined as the change in momentum experienced by an object:
where the change in momentum is given by
where m is the mass and 
is the change in velocity.
The mass is measured in kilograms (kg) while the change in velocity is measured in metres per second (m/s), therefore the units for impulse are
![[I]=[kg][m/s]](https://tex.z-dn.net/?f=%5BI%5D%3D%5Bkg%5D%5Bm%2Fs%5D)
so,
kg • meters per second
Learn more about impulse:
brainly.com/question/9484203
#LearnwithBrainly
Answer:
question5: F=74312.5N
question6: charge at the end of antenna=0.37N
Explanation:
Coulomb's law: the magnitude of the force of attraction or repulsion due to two charges is proportional to the product of the magnitude of the charges and inversely proportional to the square of distance between the charges.
⇒
∴
where 
is the force of attraction or repulsion
is Coulumb's constant=
and 
are the magnitude of the charges
is the distance between two charges
The force between the two charges is attractive if they are of different polarity
The force between the two charges is repulsive if they are of same polarity
Question5:
Given: q1=0.041 C, q2=0.029 C, r=12 m
therefore by Coulumb's law,
Question6:
Given: q1=
, r=5 m, F=
therefore by Coulumb's law,
⇒
Answer:
24cm/s
Explanation:
A=L*w
A'=L'*w'
L=13
w=5
L'=4
w'=6
A=?
A'=?
A=L*w
A=13*5
A=65
A'=L'*w'
A'=4*6
A'=24
*the given lengths are just to throw you off*
