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3 years ago

13

I need help guyssss plssss

1 answer:

Kipish [7]3 years ago

8 0

Answer:

Cd(NO3)2 + Na2S --> CdS + 2 NaNO3

Explanation:

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If an object is 16.76 cm in front of a convex mirror that has a focal length of 67.1 cm, how far behind the mirror will the imag

aniked [119]

F = focal lenght = 67.1 cm

u= distance between mirror and object = 16.76 cm

1/f = 1/v + 1/u

1/67.1 = -1/16.76 + 1/u

1/67.1 + 1/16.76 = 1/u

u = 13.41

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1 year ago

Create a list of three questions that are good science questions.

masya89 [10]

Answer:

what is speed

how to tell what speed an objeckt is moveing

vlocity

Explanation:

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3 years ago

Can someone please help me with part a and d

Temka [501]

Answer: question D is trough

Explanation: I learned this already

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3 years ago

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A 900 kg car pushes a 2400 kg truck that has a dead battery. when the driver steps on the accelerator, the drive wheels of the c

Wewaii [24]

A)0
b)magnitude of the force on the car is 500n

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3 years ago

A spaceship, at rest in some inertial frame in space, suddenly needs to accelerate. The ship forcibly expels 103 kg of fuel from

Cerrena [4.2K]

Answer:

$V_s = 1.8*10^5m/s$

Explanation:

There is no external force applied, therefore there is a moment's preservation throughout the trajectory.

<em>Initial momentum = Final momentum. </em>

The total mass is equal to

$m_T= m_1 +m_2$

Where,

$m_1 =$ mass of ship

$m_2 =$ mass of fuell expeled.

As the moment is conserved we have,

$0=V_fm_2+V_sm_1$

Where,

$V_f =$ Velocity of fuel

$V_s =$ Velocity of Space Ship

Solving and re-arrange to $V_s$ we have,

$V_s = \frac{V_f m_2 }{m_1}$

$V_s = \frac{3/5c}{10^6}$

$V_s = 3.5*10^{-3}c$

Where c is the speed of light.

Therefore the ship be moving with speed

$V_s = \frac{3}{5}*10^{-3}*3*10^8m/s$

$V_s = 1.8*10^5m/s$

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3 years ago