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n200080 [17]
3 years ago
11

If a photon has frequency = 2.00 x 1014s-1 and the speed of light = 3.00 x 108ms-1, then what is its wavelength?

Physics
1 answer:
butalik [34]3 years ago
3 0

Answer:

The photon has a wavelength of 1.5x10^{-6}m

Explanation:

The speed of a wave can be defined as:

v = \nu \cdot \lambda (1)

Where v is the speed, \nu is the frequency and \lambda is the wavelength.

Equation 1 can be expressed in the following way for the case of an electromagnetic wave:

c = \nu \cdot \lambda (2)              

 

Where c is the speed of light.    

Therefore, \lamba\lambda can be isolated from equation 2 to get the wavelength of the photon.

\lambda = \frac{c}{\nu} (3)

\lambda = \frac{3.00x10^{8}m/s}{2.00x10^{14}s^{-1}}

\lambda = 1.5x10^{-6}m

Hence, the photon has a wavelength of 1.5x10^{-6}m        

<em>Summary:  </em>

Photons are the particles that constitutes light.

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We say

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1/2mv^2 = mCv∆T/M

Making ∆T subject of the formula we have

∆T = Mv^2/2Cv

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Answer:

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