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3 years ago

11

PLEASE HELP ASAP

1 answer:

morpeh [17]3 years ago

7 0

A is the correct answer

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Answer:

Explanation:

a ) Velocity vs time graph will be a straight line with negative slope , making a slope of 2 because slope of v-t graph gives the value of acceleration.

b ) v = 0 , u = 28 m/s

t = ?

v = u - at

0 = 28 - 2 t

t = 14 s

shuttle velocity will become zero after 14 sec.

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4 years ago

An airplane takes off a runway at a constant speed of 49m/s at constant angle 30 to the horizontal

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Complete Question

An airplane takes off a runway at a constant speed of 49 m/s at constant angle 30 to the horizontal.How high (in meters ) is the airplane above the ground 13 seconds after takeoff?

Answer:

The height is $H = 318.5 \ m$

Explanation:

From the question we are told that

The speed at which the plane takes off is $u = 49 \ m/s$

The angle at which it takes off is $\theta = 30 ^o$

The time taken is $t = 13 s$

The vertical distance traveled is mathematically represented as

$H = u sin \theta t$

Substituting values

$H = (49) * sin (30) *13$

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3 years ago

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3 years ago

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Answer:

Th answer is 1-

Explanation:

trust me i have this all on the periodic table thing my school gave lol

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